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Verizon [17]
2 years ago
10

le="\frac{4}{5} p + 6 = -\frac{1}{3}p -3" alt="\frac{4}{5} p + 6 = -\frac{1}{3}p -3" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Likurg_2 [28]2 years ago
8 0
P= - 135/7 I am pretty sure that’s the answer
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A system of linear equations contains two equations with negative reciprocal slopes. How many solutions will it have?
Yanka [14]

Answer:

1 solution

Step-by-step explanation:

3 0
2 years ago
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Which describes the difference between the graph of f(x) = x2 and g(x) = -(x2 - 2)?
spin [16.1K]

Answer: B; here's a brief explanation as to why:

g(x) is an equation that has a -1 being distributed to both x^2 and -2, making the equation really -x^2 + 2,

the - in x^2 would flip the line on the X axis, while the + 2 would raise the line up by two

6 0
3 years ago
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The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
Anit [1.1K]

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

One of the polynomial which are added up is : 2d^5-c^3d^2+8cd^4+1

Let the other polynomial be 'x'

According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)

Solving the like terms in above equation we get:

x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)

x=6d^5-2c^3d^2+5c^2d^3-12cd^4+8

Hence, the correct option is A.

5 0
3 years ago
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Mrs. Carter puts a variety of wrapped chocolate candies into a bag. There are 5 silver-wrapped candies, 1 purple-wrapped candy,
Fantom [35]

Answer:

a

Step-by-step explanation:

it won't be 5

nor 60

and it won't be 15

3 0
3 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
2 years ago
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