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Mrrafil [7]
3 years ago
10

Luke, Kira and Ali each served 2/3 of their own cake. Each cake was the same size, but luke served 4 slices, Kira served 6 slice

s and Ali served 8 slices. How is this possible?
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:

The whole slices of the cakes of Luke, Kira and Ali are 6, 9 and 12 respectively. So it is possible.

Step-by-step explanation:

It's possible because they cut cakes into different number of slices.

You know that Luke, Kira and Ali each served \frac{2}{3} of their own cake and Luke served 4 slices, Kira served 6 slices and Ali served 8 slices.

Being x the whole slices of cake, and if Luke served \frac{2}{3} of his cake, which are 4 slices, the whole slices of cake of Luke is:

\frac{2}{3}*x=4 slices

Solving:

x= 4 ÷\frac{2}{3}

x= 6

Then, whole slices of Luke's cake is 6.

Performing the same approach for Kira you get:

\frac{2}{3}*x=6 slices

x= 6 ÷\frac{2}{3}

x= 9

Then, whole slices of Kira's cake is 9.

Finally, performing the same approach for Ali you get:

\frac{2}{3}*x=8 slices

x= 8 ÷\frac{2}{3}

x= 12

Then, whole slices of Ali's cake is 12.

<u><em>The whole slices of the cakes of Luke, Kira and Ali are 6, 9 and 12 respectively. So it is possible.</em></u>

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