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3 years ago

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Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

8 0

15. When the same two digits are next to each other in a number, the value of the number to the left is ten times the value of the one to the right. This is because we count in base ten and each place value represents the digit multiplied by 10^x.

16. 5,771 The one in the hundred place has a value of 7*100 which is 700. The one in the tens place has a value of 7*10 which is 70. The answer is B.

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To obtain the graph of y=(x- 8)2 shift the graph of y= x2

bonufazy [111]

You would shift this to the right 8 places. This is because in vertex form, the x value is the opposite of the number in the parenthesis with the x.

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3 years ago

Read 2 more answers

A blimp provides aerial television views of a tennis game. The television camera sights the stadium at a 17degrees angle of depr

BaLLatris [955]

Answer:

1379.31meters is the line-of-sight distance from the television camera to the base of the stadium .

Step-by-step explanation:

As given

A blimp provides aerial television views of a tennis game.

The television camera sights the stadium at a 17degrees angle of depression. The altitude of the blimp is 400m.

Now by using the trignometric identity .

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

As the figure is given below .

Perpendicular = AC = 400 m

Hypotenuse = AB

$\theta = 17^{\circ}$

Putting all the values in the identity .

$sin17^{\circ} = \frac{400}{AB}$

$0.29\ (Approx)= \frac{400}{AB}$

$AB= \frac{400}{0.29}$

AB = 1379.31 meters

Therefore the 1379.31 meters is the line-of-sight distance from the television camera to the base of the stadium .

3 0

3 years ago

g Suppose a factory production line uses 3 machines, A, B, and C for making bolts. The total output from the line is distributed

Vladimir [108]

Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

$P(D) = P(A\cap D) + P(B\cap D) + P(C\cap D)$

Recall that given events E,F the conditional probability of E given F is defined as

$P(E|F) = \frac{P(E\cap F)}{P(F)}$ , from where we deduce that

$P(E\cap F) = P(E|F)P(F)$ .

We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

$P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345$