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Marizza181 [45]
2 years ago
12

Find the slope and y intercept of 2y +8 = 6x + 4

Mathematics
2 answers:
cricket20 [7]2 years ago
8 0
Slope (3) y intercept (0,-2)
jek_recluse [69]2 years ago
6 0

Answer: y = 3x -2

Slope =3

Y-intercept = -2

Step-by-step explanation:

2y+8 = 6x + 4

Subtract 8 on both sides.

2y = 6x -4

Divide by 2. 2y divided by 2 leaves just y. 6x divided by 2 is 3x. -4 divided by 2 is -2.

Hopefully I did this correctly and it helps you!

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Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis
Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

f(x)=6

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

f(x)=-3

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

f(x)=1

Therefore the graph represents a piecewise function, which is defined as

f(x)=\begin{cases}6& \text{ if } x2 \end{cases}

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

lim_{x\rightarrow 2^-}f(x)=6

lim_{x\rightarrow 2^+}f(x)=-3

6\neq-3

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0
2 years ago
Read 2 more answers
Please help me out :))))))
Ugo [173]

Answer:

83 degree because it is 180-97

7 0
3 years ago
Which of the following is true of the discriminant for the graph below
aniked [119]

Answer:

Step-by-step explanation:

The discriminant is used to determine the number and nature of the zeros of a quadratic. If the discriminant is positive and a perfect square, there are 2 rational zeros; if the discriminant is positive and not a perfect square, there are 2 rational complex zeros; if the discriminant is 0, there is 1 rational root; if the discriminant is negative, there are no real roots.

The roots/solutions/zeros of a quadratic are where the graph goes through the x axis. Those are the real zeros, even if they don't fall exactly on a number like 1 or 2 or 3; they can fall on 1.32, 4.35, etc. They are still real. If the graph doesn't go through the x-axis at all, the zeros are imaginary because the discriminant was negative and you can't take the square root of a negative number. As you can see on our graph, the parabola never goes through the x-axis. Therefore, the zeros are imaginary because the discriminant was negative. Choice C.  Get familiar with your discriminants and the nature of quadratic solutions. Your life will be much easier!

4 0
2 years ago
12=15(z−51​)<br> What is Z
professor190 [17]

Answer:

51.8

Step-by-step explanation:

Multiply 15 by z and -51 which would equal (15z-765).

Add 765 to 12 and that equals 777

Divide 777 by 15 which would equal 51.8

4 0
3 years ago
The price of a pair of shoes is $28. The sales tax rate is 2.39 percent. What is the total amount you would pay if you bought th
Nadya [2.5K]
0.0239 x 28 = .6692 (this is the amount of tax paid)
shoes + tax = total
$28 + 0.6692 = $28.6692 which rounds to $28.67 (money is always rounded to the hundredths place)
6 0
2 years ago
Read 2 more answers
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