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3 years ago

9

A tree initially measured 3812 feet tall. Over the next 512 years, it grew to a final height of 4912 feet. During those 512 year

s, what was the average yearly growth rate of the height of the tree?

1 answer:

Arlecino [84]3 years ago

3 0

Answer:

2 feet per year

Step-by-step explanation:

I think you meant 38 1/2

and 5 1/2

but if you didn't then its

2.1484375

because

4912-3812=1100

1100÷512= 2.1484375

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1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

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Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

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2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

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Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

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