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velikii [3]
3 years ago
5

Can someone please help me with this problem

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
5 0
X= 2/3

6x/x-6 - 4/x - 24 / x^2 - 6x = 0


6x^2 -4 (x-6)-24 / x(x-6) = 0

6x^2 -4x+ 24 -24/x(x-6) = 0

X(6x-4) / x(x-6)

6x-4/x-5 = 0

6x-4= 0

6x = 4 divide both sides by 6
X= 2/3
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R, S, Q and P are the midpoints of OC, CB, BA and OA respectively.
Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

Draw segment OB.

In triangle OBC, points R and S are the midpoints of sides OC and BC, respectively. That makes RS parallel to OB.

In triangle OBA, points P and Q are the midpoints of sides OA and BA, respectively. That makes PQ parallel to OB.

Since segments RS and PQ are parallel to segment OB, then RS and PQ are parallel to each other.

3 0
2 years ago
If x+3 is a factor of x^3-x^2-10x+A. What is the value of A?
Leno4ka [110]

Answer:

A = 6.

Step-by-step explanation:

Let a denote a constant (a number, rather than a variable like x.)

Let f(x) denote an expression about x (for example,

By the factor theorem, if (x - a) is a factor of f(x), then f(a) = 0. In other words, if all mentions of x in the expression f(x)\! are replaced with a, then the expression should evaluate to zero.

(x + 3) is equivalent to (x - (-3)). That is: a = -3.

Replace all mentions of x in x^3 - x^2 - 10\, x + A by (-3) to get:

(-3)^3 - (-3)^2 - 10\times (-3) + A.

That should evaluate to zero. Therefore: -27 - 9 + 30 + A = 0. Solve for A to get A = 6.

7 0
3 years ago
Find the coefficient of the x^3 in the expansion of (2x-9)^5
il63 [147K]

Use the binomial theorem:

\displaystyle (2x-9)^5 = \sum_{k=0}^5 \binom5k (2x)^{5-k}(-9)^k = \sum_{k=0}^5 \frac{5!}{k!(5-k)!} 2^5 \left(-\frac92\right)^k x^{5-k}

The <em>x</em> ³ terms occurs for 5 - <em>k</em> = 3, or <em>k</em> = 2, and its coefficient would be

\dfrac{5!}{2!(5-2)!} 2^5 \left(-\dfrac92\right)^2 = \boxed{6480}

8 0
3 years ago
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baherus [9]

Answer:

How tall is he semicirlce?

Step-by-step explanation:

Then I can solve

4 0
3 years ago
Which word describes the unit price​
Pavlova-9 [17]
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2 years ago
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