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Fofino [41]
3 years ago
8

This cuboid is made from centimetre cubes. a) write down the volume of the cuboid, b) the cuboid is then split apart into one of

these smaller cuboids. How many of these can be made?

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
6 0
A
hope this helps:))))
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I need to no what’s the answer from these question.
MaRussiya [10]
What’s the question?
8 0
3 years ago
Solve the equation and justify the steps used to solve. <br> -7=n-6
Oksanka [162]

Answer:

-1

Step-by-step explanation:

-7=n-6

n=-7+6

n=-1

Please mark me as Brainliest if you're satisfied with the answer.

5 0
3 years ago
Multiplication Property of One<br> 1⋅w⋅16
expeople1 [14]

Answer:

The correct answer is 16w.

Step-by-step explanation:

w = 1w

1⋅w⋅16 =

1⋅1w⋅16 =

16w

Therefore, the correct answer is 16w.

Hope this helps! :D

7 0
3 years ago
An equilateral triangle is inscribed in a circle of radius 6r. Express the area A within the circle but outside the triangle as
Paul [167]

Answer:

A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}

Step-by-step explanation:

We have been given that an equilateral triangle is inscribed in a circle of radius 6r. We are asked to express the area A within the circle but outside the triangle as a function of the length 5x of the side of the triangle.

We know that the relation between radius (R) of circumscribing circle to the side (a) of inscribed equilateral triangle is \frac{a}{\sqrt{3}}=R.

Upon substituting our given values, we will get:

\frac{5x}{\sqrt{3}}=6r

Let us solve for r.

r=\frac{5x}{6\sqrt{3}}

\text{Area of circle}=\pi(6r)^2=\pi(6\cdot \frac{5x}{6\sqrt{3}})^2=\pi(\frac{5x}{\sqrt{3}})^2=\frac{25\pi x^2}{3}

We know that area of an equilateral triangle is equal to \frac{\sqrt{3}}{4}s^2, where s represents side length of triangle.

\text{Area of equilateral triangle}=\frac{\sqrt{3}}{4}s^2=\frac{\sqrt{3}}{4}(5x)^2=\frac{25\sqrt{3}}{4}x^2

The area within circle and outside the triangle would be difference of area of circle and triangle as:

A(x)=\frac{25\pi x^2}{3}-\frac{25\sqrt{3}x^2}{4}

We can make a common denominator as:

A(x)=\frac{4\cdot 25\pi x^2}{12}-\frac{3\cdot 25\sqrt{3}x^2}{12}

A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}

Therefore, our required expression would be A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}.

7 0
3 years ago
HELP!!!!
Lera25 [3.4K]

Answer:

  • a. the y-intercept of f(x) is greater than the y-intercept of g(x)

Step-by-step explanation:

<u>Given function:</u>

  • f(x)=(x - 4)^2 - 4

<u>We can work out the function from the table values:</u>

  • g(x) = (x + 2)^2 - 4

<u>Options:</u>

a. the y-intercept of f(x) is greater than the y-intercept of g(x)

  • True. x= 0 ⇒ f(0) = (-4)^2 - 4 = 12, g(0) = 2^2 - 4 = 0

b. The y-intercept of g(x) is greater than the y-intercept of f(x)

  • False. See previous option.  

c. The y-coordinate of the vertex of f(x) s greater than the y-coordinate of the vertex of g(x)

  • False. They are same = -4

d. The x-coordinate of the vertex of g(x) is greater than the x-coordinate of the vertex of f(x)

  • False. -2 vs 4
7 0
3 years ago
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