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Harrizon [31]
4 years ago
12

In which quadrant would you find the point 4 and 8

Mathematics
1 answer:
MrMuchimi4 years ago
4 0

Answer:

Quadrant 1

Step-by-step explanation:

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Solve pls brainliest
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yes

Step-by-step explanation: brainly

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Find the quotient: –3.5 and –0.875<br> –40<br> –4<br> 4<br> 40
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Which of the following possibilities will form a triangle?
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C

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The sum of any two sides must be equal to more than the length of the third side.

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Florida has 8 less than 5 times the number of counties in Arizona. Write an expression that represents the number of counties in
nikitadnepr [17]

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4 0
3 years ago
The weights of bags of peas are normally distributed with a mean of 13.50 ounces and a standard deviation of 1.06 ounces. Bags i
Pepsi [2]

Answer:

The most that a bag can weigh and not need to be repackaged is 15.355 ounces.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 13.50, \sigma = 1.06

Bags in the upper 4% are too heavy and must be repackaged. What is the most that a bag can weigh and not need to be repackaged?

Bags in the upper 4% have a pvalue of 1-0.04 = 0.96. So the most that a bag can weight and not need to be repackaged is the value of X when Z has a pvalue of 0.9599. So this is X when Z = 1.75

Z = \frac{X - \mu}{\sigma}

1.75 = \frac{X - 13.50}{1.06}

X - 13.50 = 1.75*1.06

X = 15.355

The most that a bag can weigh and not need to be repackaged is 15.355 ounces.

5 0
3 years ago
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