Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
10x^4y^4+2x^6-15y^6-3x^2y^2
Answer:
The answer is B
Step-by-step explanation:
Each smaller rectangle is being multiplied by <em>a </em>so 2a + 3a + 4a would give you the total area of the entire large rectangle.
Taking v to be y, it's written in the standard form for a linear equation, y=mx+c
Draw a straight, horizontal line. Mark evenly-spaced scale divisions, 0 to 5 (because all of the given numerals fit within this domain).
Recognize that the LCD of these fractions and mixed numbers is 6.
Convert all of the given fractions to denominator 6, as needed (some already have that denominator).
Arrange the resulting fractions in ascending order. For example, 5/6, 1/6, 3/6 would become 1/6, 3/6, 5/6 (in ascending order).
Plot all your numerals (all of which have denominator 6) on your number line.
