Answer:
0.149 s or 0.15 s
Explanation:
let initially ball is moving towards left hence initial velocity = - 28.62 m/s
final velocity as ball moves right = +20 m/s
force = rate of change in momentum
force = mass × change in velocity / time
or time = mass × change in velocity / force
time = 2× ( 20 -( -28.62)) / 652.36
time = 2× ( 20 +28.62)) / 652.36
time = 2× 48 .62/652.36
time = 0.149 s or 0.15 s
Answer:
1- For the track B. The potential energy is the same for the two cars, but because of the slope of the track, the car B earn kinetic energy faster. The gravitation acceleration of the cars will be g•sinθ, and the angle of the track B will have a bigger value for sinθ
2- The conservation of energy applies because the roller coaster is a closed track. When a car climb the track, it earn GPE, which is given by mgh, when it get down in the track, it transform GPE in KE, which is given in 1/2mv².
3-
Position of car (m) GPE KE GPE + KE
top (30m) 60000 0 60000
bottom (0m) 0 60000 60000
halfway down (15m) 30000 30000 60000
three-quarters way down 15000 45000 60000
Answer:
0.306mm
Explanation:
The radius of the conductor is 3mm, or 0.003m
The area of the conductor is:
A = π*r^2 = π*(.003)^2 = 2.8*10^-5 m^2
The current density is:
J = 130/2.8*10^-5 = 4.64*10^6 A/m
According to the listed reference:
Vd = J/(n*e) = 4.64*10^6 / ( 8.46*10^28 * 1.6*10^-19 ) = 0.34*10^-6 m/s = 0.34mm/s
The distance traveled is:
x = v*t = 0.34 * .90 = 0.306 mm
Answer:
Heat transfer in the process is -19.6 kJ
Work done in the process is - 28 kJ
Explanation:
As we know that the process equation is given as
now we know that
now from above equation we have
now work done in this process is given as
here we know N = 1.1
so we have
Now we have
now we have
so we have