Answer:
Clock on the satellite is slower than the one present on the earth = 29.376 s
Given:
Distance of satellite from the surface, d = 250 km
Explanation:
Here, the satellite orbits the earth in circular motion, thus the necessary centripetal force is provided by the gravitation force and is given by:

where
v = velocity of the satellite
R = radius of the earth = 6350 km = 6350000 m
G = gravitational constant = 
M = mass of earth = 
Therefore, the above eqn can be written as:

Now, for relativistic effects:

Now,
r = R + 250

Ratio of rate of satellite clock to surface clock:

Clock on the satellite is slower than the one present on the earth:

Answer:
As a freely falling object picks up downward speed. What happens to the power supplied by the gravitational force? Does it increase, decrease or stay the same? The power will increase because (Power=work/time; work=f(d); and F x d/t; FV).
Explanation:
Answer: energy of photon = 96Mev or 1.536x10^-11 J
Wavelenght is 1.3085x10^-14
Explanation:
Detailed explanation and calculation is shown in the image below