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FromTheMoon [43]
4 years ago
8

Can someone help me with this really quick please

Physics
1 answer:
AlekseyPX4 years ago
8 0

Apple juice is a homogeneous mixture. That means when you look through it, you can't see anything but  a liquid with your naked eye. The color is constant. Then how do you know there is something else in there? The color gives you the hint you need. Pure water is colorless in liquid form.

The salad dressing might be a solution and it can be made to temporarily mix when you shake it, but it will soon separate into oil and a water based acid usually vinegar.

Filtering wouldn't affect the apple juice. Whatever is in there will go through filter paper. It's like using a screen with 1 inch squares: only the largest stones would be filtered out.

Filtering might take out some of the particles in the oil / acid mixture but likely on the herbs put in. I'm not sure you should say no effect on either really.

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A sphere is originally at a temperature of 500°c. The sphere is melted and recast, without loss of mass, into a cube with the sa
aleksandr82 [10.1K]

Answer: The value of the celsius temperature of the cube is 472.2°c.

Explanation:        

The expression for the power radiated is as follows;

P=A\epsilon\sigma T^{4}

Here, A is the area, \sigma is the stefan's constant,\epsilon is the emissivity and T is the temperature.

It is given in the problem that A sphere is originally at a temperature of 500°c. The sphere is melted and recast, without loss of mass, into a cube with the same emissivity as the sphere.

Then the expression for the radiated power for the cube and the sphere can be expressed as;

A_{1}\epsilon \e\sigma T_{1}^{4}=A_{2}\epsilon \e\sigma T_{2}^{4}

Here, A_{1} is the area of the sphere, A_{2} is the area of the cube,T_{1}  is the temperature of the sphere and T_{2}  is the temperature of the cube.

The radiated powers and emissivity of the cube and the sphere are same.

A_{1}T_{1}^{4}=A_{2}T_{2}^{4}

The area of the sphere is A_{1}=4\pi \times r^{2}.

Here, r is the radius of the sphere.

The area of the cube is A_{2}=6\times a^{2}.

Here, a is the edge of the cube.

Put A_{1}=4\pi \times r^{2} and A_{2}=6\times a^{2}.

T_{2}=T_{1}(\frac{2\pi }{3}\times (\frac{r}{a})^{2})^{\frac{1}{4}}  ....(1)

The masses and the densities of the sphere and the cube are same. Then the volumes are also same.

V_{1}=V_{2}

Here,V_{1},V_{1} are the volumes of the sphere and the cube.

\frac{4}{3}\pi r^{3}=a^{3}

\frac{r}{a}=(\frac{3}{4\pi })^{\frac{1}{3}}  

Put this value in the equation (1).

T_{2}=T_{1}(\frac{2\pi }{3}\times (\frac{r}{a})^{2})^{\frac{1}{4}}T_{2}=T_{1}(\frac{2\pi }{3}\times ((\frac{3}{4\pi })^{\frac{1}{3}})^{2})^{\frac{1}{4}}

Put T_{1}=500°c.

T_{2}=(500)(\frac{2\pi }{3}\times (\frac{3}{4\pi })^{\frac{2}{3}})^{\frac{1}{4}}

T_{2}=472.2^{\circ}c

Therefore, the value of the celsius temperature of the cube is 472.7°c.    

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The magnetosphere protects Earth from _____. a.solar radiation b. the solar wind c. the cold of space d.asteroid hits e.gamma ra
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Consider an elevator carrying Kermit the frog weighing 4000.0 N is held 5.00 m above a spring with a force constant of
tigry1 [53]

Answer:

The maximum compression distance of the spring is 0.375 m

Explanation:

The given parameters are;

The weight of the elevator and the frog = 4,000.0 N

The location of the elevator above the spring = 5.00 m

The force constant of the spring, k = 8,000.0 N/m

The frictional force of the brakes = 1,000.0 N

The net force, F, of the elevator on the spring is F = 4,000.0 N - 1,000.0 N = 3,000.0 N

F = 3,000.0 N

The maximum compression distance of the spring, x is given as follows;

F = k × x

Substituting the known values gives;

3,000.0 N = 8,000.0 N/m × x

∴ x = (3,000.0 N)/(8,000.0 N/m) = 0.375 m

x = 0.375 m = 37.5 cm

The maximum compression distance of the spring, x = 0.375 m.

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