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3 years ago

CAN SOMONE PLZ HELP ME ON THS

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

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I don't know how to solve this

agasfer [191]

Answer:

Hello,

Step-by-step explanation:

using Thalès 's théorem :

$\dfrac{x}{x+10} =\dfrac{4}{10} \\\\10x=4x+40 \ (cross\ products)\\\\6x=40\\\\x=\dfrac{20}{3} \ (simplified\ by\ 2)$

x≈6.7 (i don't know what d.p. means , perhaps 1 decimal after the point)

4 0

2 years ago

The nth term of a sequence is 3n^2- 1

Thepotemich [5.8K]

Answer: The number that belongs to both sequences is 26.

Step-by-step explanation:

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √( (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √( (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √( (31 - 2^2)/3) = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

The number that belongs to both sequences is 26.

5 0

3 years ago

A jar has five different colors of gum balls in it. Blue gum balls comprise 20% of the total number of candy. There are 10 more

Maurinko [17]

Let the total number of gum balls in the jar be x, then the number of blue balls in the jar is 0.2x and the number of green balls is 10 + 0.2x and the number of red balls are 0.5(0.2x) = 0.1x.

Let the initial number of yellow balls in the jar be y, then $\frac{4}{7} = \frac{0.1x}{y} \Rightarrow4y=0.7x\Rightarrow y=0.175x$

The initial number of white balls was 0.275x.

Thus,

$x-0.2x-(10+0.2x)-0.1x-0.175x=0.275x \\ \\ \Rightarrow0.525x-10-0.2x=0.275x \\ \\ \Rightarrow0.325x-0.275x=10 \\ \\ \Rightarrow0.05x=10 \\ \\ \Rightarrow x= \frac{10}{0.05} =200$

Thus, the initial number of yellow balls was 0.175x = 0.175(200) = 35.
The initial number of white balls was 0.275x = 0.275(200) = 55.
One-fifth of white balls = 1/5(55) = 11.

Therefore, the number of yellow balls in the jar was 35 + 11 = 46.

7 0

3 years ago

Read 2 more answers

If x + y = x, show that x = 1.

Alexxx [7]

So first you would go 1+y=1 and the go 1+0=1

7 0

2 years ago

6 times itself, multiplied by 5 times itself

Pani-rosa [81]

Answer:

900