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Sedaia [141]
3 years ago
12

Calculate the average net force.

Physics
1 answer:
MrRa [10]3 years ago
3 0

Answer:

<h2><u>given</u></h2>

<em>mass</em><em> </em><em>=</em><em> </em><em>39</em><em>5</em><em>0</em><em> </em><em>kg</em>

<em>speed</em><em>=</em><em> </em><em>2</em><em>5</em><em>m</em><em>/</em><em> </em><em>sec</em>

<em>time</em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em><em>5</em><em> </em><em>sec</em>

<h2><em>To</em><em> </em><em>find</em><em> </em></h2>

<em>force</em><em> </em>

<h2><em><u>Solution</u></em></h2>

<h3><em>☄️</em><em>Formula</em><em> </em><em>of</em><em> </em><em>force</em><em> </em></h3>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>\fbox{f = m.a}</em>

<u><em>To</em><em> </em><em>find</em><em> </em><em>the </em><em>force </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the </em><em>Acceleration</em><em> </em><em>first</em><em>.</em></u>

<em>accler</em><em>ation</em><em>=</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>Velocity</em><em>/</em><em>time</em>

<em>accle</em><em>ration</em><em>=</em><em> </em><em>2</em><em>5</em><em>/</em><em>1</em><em>0</em><em>.</em><em>5</em>

<u><em>acc</em><em>leration</em><em>=</em><em> </em><em>2.38</em><em> </em><em>m</em><em>/</em><em>sec²</em></u>

<u><em>put</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>accle</em><em>ration</em><em> </em><em>in</em><em> </em><em>the </em><em>formula</em><em> of</em><em> force</em></u>

<u><em>force</em><em> </em><em>=</em><em> </em><em>Mass</em><em> </em><em>.</em><em> </em></u><em><u>accleration</u></em>

<em>force</em><em> </em><em>=</em><em> </em><em>39</em><em>5</em><em>0</em><em> </em><em>x</em><em> </em><em>2</em><em>.</em><em>3</em><em>8</em>

<h3><em>☄️</em><em>force</em><em> </em><em>=</em><em> </em><em>9,401</em><em> </em><em>Newton</em></h3>

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An airplane travels at 300 mi/h south for 2.00 h and then at 250 mi/h north for 750 miles. What is the average speed for the tri
Anettt [7]

Answer:

270 mi/h

Explanation:

Given that,

To the south,

v₁ = 300 mi/h, t₁ = 2 h

We can find distance, d₁

d_1=v_1\times t_1\\\\d_1=300\times 2\\\\d_1=600\ \text{miles}

To the north,

v₂ = 250 mi/h, d₂ = 750 miles

We can find time, t₂

t_2=\dfrac{d_2}{v_2}\\\\t_2=\dfrac{750\ \text{miles}}{250\ \text{mi/h}}\\\\t_2=3\ h

Now,

Average speed = total distance/total time

V=\dfrac{d_1+d_2}{t_1+t_2}\\\\V=\dfrac{600+750}{2+3}\\\\V=270\ \text{mi/h}

Hence, the average speed for the trip is 270 mi/h.

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3 years ago
What is the anode in an alkaline battery?
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4 years ago
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how much work did the movers do (horizontally) pushing a 41.0- kg crate 10.3 m across a rough floor without acceleration, if the
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W=2485.65 J ,work did the movers do friction force a 41.0- kg crate 10.3 m across a rough floor without acceleration

<h3>What is a basic friction force?</h3>

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<h3>What outcomes does friction produce?</h3>

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7 0
1 year ago
21. A toy car starts from rest and begins to
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Answer:

v = 66 m/s

Explanation:

Given that,

The initial velocity of a car, u = 0

Acceleration of the car, a = 11 m/s²

We need to find the final velocity of the toy after 6 seconds.

Let v is the final velocity. It can be calculated using first equation of motion. It is given by :

v = u +at

v = 0 + 11 m/s² × 6 s

v = 66 m/s

So, the final velocity of the car is 66 m/s.

8 0
3 years ago
A monatomic ideal gas initially fills a container of volume V = 0.25 m3 at an initial pressure of P = 250 kPa and temperature T
Murrr4er [49]

Answer:

number of moles = 27.34 moles

the temperature of gas after it undergoes the isobaric expansion = 605 K

Explanation:

Given that:

V = 0.25 m³

P = 250 kPa

T = 275 K

V₂ = 0.55 m³

P₂ = 760 kPa

a)

Using ideal gas equation ; PV = nRT

n = \frac{PV}{RT}\\\\n =  \frac{250*10^3*0.25}{8.314*275}\\\\n = \frac{62500}{2286.35}\\\\n = 27.34 \ moles

b) To calculate the temperature of gas after it undergoes the isobaric expansion; we have:

  1. \frac{V_1}{T_1}= \frac{V_2}{T_2}\\\\\frac{0.25}{275}= \frac{0.55}{T_2}\\\\T_2=\frac{0.55*275}{0.25}\\\\T_2 = 605 K

4 0
4 years ago
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