Answer:
a) 16m/s b) 192m
Explanation:
v1=32m/s a=-2m/s^2 t=8s v2=? d=??
a) I will use this equation v2= v1 + a*t
v2= 32m/s + -2m/s^2 * 8s
v2= 32m/s + -16m/s
v2= 16m/s
b) v2^2=v1^2 + 2ad
rearranging
v2^2-v1^2=2ad
v2^2-v1^2/2= a d
v2^2-v1^2/2a=d
16m/s^2 - 32m/s^2/ 2 x-2m/s^2 =d
d=192m
Answer:
50 KeV
Explanation:
50 KeV will be the most likely initial interaction with tissue.
Because Higher the energy lesser will the interaction with tissues, Because it will penetrate through tissue more easily in a very lesser time Whereas the photon with least energy will take more time to penetrate through the tissue, hence, higher interaction with tissue.
(A "release" of a chemical means that it is emitted to the air or water, or placed in some type of land disposal.)
Answer:
The correct option is: A) As Earth goes around the Sun and Earth's axis remains pointed toward Polaris, the Northern and Southern hemispheres alternately receive more and less direct sunlight.
Explanation:
Seasons on Earth are the changes in the weather caused due to the <u>titled axis of the Earth, relative to the orbital or ecliptic plane</u>, while orbiting around the Sun. The Earth's axis of rotation is<u> tilted approximately by an angle of 23.4°. </u>
This results in the change in the intensity of the sunlight received by the Earth's surface, due to which the southern and the northern hemispheres <u>experience opposite seasons.</u>
Answer: vl = 2.75 m/s vt = 1.5 m/s
Explanation:
If we assume that no external forces act during the collision, total momentum must be conserved.
If both cars are identical and also the drivers have the same mass, we can write the following:
m (vi1 + vi2) = m (vf1 + vf2) (1)
The sum of the initial speeds must be equal to the sum of the final ones.
If we are told that kinetic energy must be conserved also, simplifying, we can write:
vi1² + vi2² = vf1² + vf2² (2)
The only condition that satisfies (1) and (2) simultaneously is the one in which both masses exchange speeds, so we can write:
vf1 = vi2 and vf2 = vi1
If we call v1 to the speed of the leading car, and v2 to the trailing one, we can finally put the following:
vf1 = 2.75 m/s vf2 = 1.5 m/s
