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abruzzese [7]
3 years ago
12

If the loading is 0.4, the coinsurance rate is 0.2, the number of units of medical care is 100, and the number of units of medic

al care is 1. What is the premium of this insurance?
Physics
1 answer:
s344n2d4d5 [400]3 years ago
8 0

Answer:

72  is the premimum of the insurance.

Explanation:

Below is the given values:

The loading = 0.4

Coinsurance rate = 0.2

Number of units = 100

Total number of units = 100 * 0.4 = 40

Remaining units = 60 * 0.2 = 12

Add the 60 and 12 values = 60 + 12 = 72

Thus, 72  is the premimum of the insurance.

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A chemical property is a change in _____.
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A chemical property is a change in classification in matter I think
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3 years ago
During aerobic activity, if your heart rate is lower than the lower limit, you are ___________________.
soldier1979 [14.2K]
Not pushing yourself hard enough is the answer since your heart rate doesn't even hit your lower minimum.
Pushing yourself to the limit is at your max heart rate.
Just at the right spot is at your max heart rate.
Pushing yourself too hard is above your max heart rate.
4 0
4 years ago
(b) A cylinder of cross-sectional area 0.65m2 and
VLD [36.1K]

Answer:

The volume of the cavity is 0.013m^3

Explanation:

To find the volume of the cavity, the major parameter missing is the diameter of the cavity itself. we can obtain this using the following steps:

Step one:

Obtain the volume of the cylinder by dividing the mass of the cylinder by the density.

Volume of the cylinder = 2.1 / 11.053 =0.19m^{3}

Step two:

From the volume of the cylinder, we can get the radius of the cylinder.

radius = \sqrt{\frac{V}{\pi \times h}}  = \sqrt{\frac{0.19}{\pi \times 0.32}} =0.44m

Step three:

From the cross-sectional area, we can obtain the radius of the cavity.

Let the radius of the cavity be = r, while the radius of the cylinder be = R

CSA of cavity =

\pi({R^2}-r^2) = CSA\\0.65 = \pi (0.32^2-r^2)\\r= 0.115m

Step Four:

calculate the volume of the cavity using volume =\pi r^2 \times h

Recall that the cavity has the same height as the original cylinder

volume = \pi \times 0.115^2\times 0.32= 0.013m^3

8 0
3 years ago
A ball is tossed vertically upwards with a speed of 5.0 m s–1. After how many seconds will the ball return to its initial positi
mezya [45]

Answer:

1.02 seconds

Explanation:

Initial velocity = u = 5 m/s

t = Time taken

s = Displacement travelled = 0

a = Acceleration due to gravity = -9.81 m/s² (negative sign due to direction)

Equation of motion

s=ut+\frac{1}{2}at^2\\\Rightarrow 0=5t+\frac{1}{2}-9.81\times t^2\\\Rightarrow 0=5t-4.905t^2\\\Rightarrow 0=t(5-4.905t)\\\Rightarro 0=5-4.905t\\\Rightarrow t=\frac{-5}{-4.905}=1.02\ seconds

So, time taken to return to its initial position is 1.02 seconds

7 0
4 years ago
Gasoline flows in a long, underground pipeline at a constant temperature of 15o C (rho = 680 kg/m3 ; ν = 4.6 × 10-7 m2 /s). Two
poizon [28]

Answer:

1.0416 m∧3/sec

Explanation:

check the pictures below for the solution

8 0
3 years ago
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