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dybincka [34]
2 years ago
8

An outside force, Fo, brings two small metal spheres, A and B, at rest from a long distance away to a point where they are 1 met

ers apart. They are then connected by a non-conducting string of negligible mass. The spheres have mass mA = 5.8 g and mB = 9.5 g and both have equal positive charges of 5 μC. (You may assume the length of the string is much greater than the radii of the spheres.)
1)What was the total work done by the outside force to bring the spheres to the point described?
2)What was the total work done by the electric field when the two sphere were brought together as described?
3)What is the potential energy of the two sphere system after they have been brought together as described? (You may assume the spheres had zero potential energy when they were a long distance apart.)
4)Suppose you cut the string. At that instant, what is the magnitude of the acceleration of sphere A?
5)At that instant, what is the magnitude of the acceleration of sphere B?
6)After a very long time, what is the magnitude of the velocity of sphere A?
7)After a very long time, what is the magnitude of the velocity of sphere B?

Physics
1 answer:
Ksenya-84 [330]2 years ago
4 0

Answer:

1)

The total work done by outside force is W_{o}=0.294J

2)

The total work done by the electric field is -W_{o} =-0.294J

3)

The potential energy of the two sphere system is  PE = W_{o} = 0.294J

4)

The magnitude of the acceleration of sphere A is a_{A} = 66.868m/s^2

5)

The magnitude of the acceleration of sphere B is a_{B} = 26.747 \ m/s^2

6)

The magnitude of velocity sphere A after a very long time is  v_{A} = 10.251 \ m/s\

7) The magnitude of velocity sphere B after a very long time is  v_{B} = 4.1 m/s

 

Explanation:

The explanation is shown on the first and second uploaded image

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7 0
3 years ago
A 103 kg physics professor has fallen into the Grand Canyon. Luckily, he managed to grab a branch and is now hanging 93 m below
siniylev [52]

Answer:

125.83672 seconds

Explanation:

P = Power of the horse = 1 hp = 746 W (as it is not given we have assumed the horse has the power of 1 hp)

m = Mass of professor = 103 kg

g = Acceleration due to gravity = 9.8 m/s²

h = Height of professor = 93 m

Work done would be equal to the potential energy

W=mgh\\\Rightarrow W=103\times 9.8\times 93\\\Rightarrow W=93874.2\ J

Power is given by

P=\frac{W}{t}\\\Rightarrow t=\frac{W}{P}\\\Rightarrow t=\frac{93874.2}{746}\\\Rightarrow t=125.83672\ seconds

The time taken by the horse to pull the professor is 125.83672 seconds

6 0
3 years ago
when approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately
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Once the gasoline charge has been cleared, start the engine manually or with an electric starter while cutting the ignition and using the maximum throttle.

On the final approach, the aeroplane needs to be re-trimmed to account for the altered aerodynamic forces. A substantial nose-down tendency results from the airflow producing less lift on the wings and less downward force on the horizontal stabiliser due to the reduced power and slower velocity.

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7 0
1 year ago
Initially sliding with a speed of 1.9 m/s, a 1.8 kg block collides with a spring and compresses it 0.35 m before coming to rest.
Alika [10]
Let k =  the force constant of the spring (N/m).

The strain energy (SE) stored in the spring when it is compressed by a distance x=0.35 m is
SE = (1/2)*k*x²
     = 0.5*(k N/m)*(0.35 m)²
     = 0.06125k J

The KE (kinetic energy) of the sliding block is
KE = (1/2)*mass*velocity²
     = 0.5*(1.8 kg)*(1.9 m/s)²
     = 3.249 J

Assume that negligible energy is lost when KE is converted into SE.
Therefore
0.06125k = 3.249
k = 53.04 N/m

Answer:  53 N/m  (nearest integer)

3 0
3 years ago
Spaceship 1 and spaceship 2 have equal masses of 200 kg. Spaceship 1 has a speed of 0 m/s, and spaceship 2 has a speed of 10 m/s
m_a_m_a [10]

Answer:

2000 kg m/s

Explanation:

The momentum of an object is a vector quantity whose magnitude is given by

p=mv

where

m is the mass of the object

v is the velocity of the object

and its direction is the same as the velocity.

In this problem, we have:

- Spaceship 1 has

m = 200 kg (mass)

v = 0 m/s (zero velocity)

So its momentum is

p_1 =(200)(0)=0

- Spaceship 2 has

m = 200 kg (mass)

v = 10 m/s (velocity)

So its momentum is

p_2=(200)(10)=2000 kg m/s

Therefore, the combined momentum of the two spaceships is

p=p_1+p_2=0+2000=2000 kg m/s

3 0
3 years ago
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