4 years ago

1\(x^2-2x-3=6/x+4 solve problem with steps

Mathematics

1 answer:

Eduardwww [97]4 years ago

7 0

I wrote the answer and took it.

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3 years ago

Find the TWO integers whos product is -12 and whose sum is 1<br>

Deffense [45]

Answer:

$\rm Numbers = 4 \ and \ -3.$

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

$\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}$

Hence the numbers are 4 and -3

4 0

3 years ago

Read 2 more answers