Answer:
A) 14.3606 ft
B) 2.8112 seconds
Step-by-step explanation:
A) At maximum height which is its peak, the velocity will be zero.
Now, we are given height modeled by;
h(t) = 4.98t² - 14t + 20
v(t) = dh/dt = 9.96t - 14.
At max height which is v(t) = 0, we have;
9.96t - 14 = 0
9.96t = 14
t = 14/9.96
t = 1.4056 s
Thus, height at this time is;
h(1.4056) = 4.98(1.4056)² - 14(1.4056) + 20
h(1.4056) = 14.3606 ft
B) time of flight = 2 × time to get to peak = 2 × 1.4056 = 2.8112 seconds.
