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zalisa [80]
4 years ago
7

What is the solution to the following system

Mathematics
2 answers:
zzz [600]4 years ago
3 0

(4, -1, 3) \:  is  \: the \:  answer.
Neporo4naja [7]4 years ago
3 0

Answer:

Option C. (4, -1, 3)

Step-by-step explanation:

The given system of equations is

x + y + z = 6 -----(1)

x - y + z = 8 ------(2)

x + y - z = 0 -----(3)

We subtract equation 1 by 3

(x + y + z) - (x + y - z) = 6 - 0

z + z = 6

2z = 6

z = 3

Now we subtract equation 1 by 2

(x + y + z) - (x - y + z) = 6 - 8

2y = -2

y = -1

Now we put the values of x and y in equation 1

x + (-1) + 3 = 6

x + 2 = 6

x = 6 - 2 = 4

Therefore, the solution of the equations is (4, -1, 3).

Option C is the answer.

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ArbitrLikvidat [17]

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3(2x+9)=6x+27

therefore

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Part S)  8(3x+1)=+8

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8(3x+1)=24x+8

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23-----> S

<u>Part O)</u>  a(4+b)=+ab

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a(4+b)=4a+ab

therefore

<u>the answer Part O is</u>

17-----> O  

<u>Part E)</u> x(y+10)=+10x

Using the distributive property

x(y+10)=xy+10x

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<u>the answer Part E is</u>

3-----> E

<u>Part I)</u> 2(7x+4y)=14x+

Using the distributive property

2(7x+4y)=14x+8y

therefore

<u>the answer Part I is</u>

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<u>Part D)</u> 6(9+5x)=54+

Using the distributive property

6(9+5x)=54+30x

therefore

<u>the answer Part D is</u>

10-----> D  

<u>Part W)</u> x(a+3b)=+3bx

Using the distributive property

x(a+3b)=ax+3bx

therefore

<u>the answer Part W is</u>

18-----> W

<u>Part E)</u> a(8x+2y)=8ax+

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a(8x+2y)=8ax+2ay

therefore

<u>the answer Part E is</u>

7-----> E

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<u>Part T)</u> 0.5(4a+10)=2a+5

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<u>the answer Part T is</u>

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(2/3)(12+9y)=8+6y

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<u>the answer Part R is</u>

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<u>the answer Part O is</u>

13-----> O

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9a+9b=9(a+b)

therefore

<u>the answer Part T is</u>

22-----> T

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4m+4n=4(m+n)

therefore

<u>the answer Part W is</u>

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<u>Part H)</u> ab+3a=a(b+\ )

ab+3a=a(b+3)

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<u>the answer Part H is</u>

2-----> H  

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xy+15x=x(y+15)

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bu+uv=u(b+v)

therefore

<u>the answer Part A is</u>

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(2/5)m+(2/5)n=(2/5)(m+n)

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(3/4)a+(3/4)b+(3/4)c=(3/4)(a+b+c)

therefore

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8-----> M  

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therefore

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19-----> R

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4 0
3 years ago
Read 2 more answers
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<h3>Need to Do :- </h3>
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\rule{200}4

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