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Kipish [7]
3 years ago
5

Sometimes the units for an electric field are written as N/C, while other times the units are written as V/m, using dimensional

analysis show that N/C is equal to V/m.
a. True
b. False
Physics
1 answer:
White raven [17]3 years ago
5 0

Answer:

N/C = V/m.

Explanation:

The SI unit of electric field is N/C. Sometimes the units are written as V/m.

We know that,

1 V = 1 J/C

Using dimensional analysis,

The dimensional formula for Joules is [M¹L² T⁻²].

The dimensional form of coulomb is [M⁰ L⁰ T¹ I¹].

So,

J/C = [M¹L² T⁻³I¹] ...(1)

The dimensional formula of Newton is [M¹ L¹ T⁻²]

The dimensional form of coulomb is [M⁰ L⁰ T¹ I¹].

N/C= [M¹L² T⁻³I¹] ....(2)

From (1) and (2) it is clear that the N/C is equal to V/m.

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An object with velocity 141 ft/s has a kinetic energy of 1558.71 ft∙lbf, on a planet whose gravity is 31.5 ft/s2. What is its
Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m  = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \  \times \ \ \ \ 1   \ lbf\ }

m  = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm

Therefore, the mass of the object is 5.045 lbm.

6 0
3 years ago
Laundry in a clothes dryer often becomes charged with static electricity while drying. Which of these best explains why a clothe
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A stone is thrown horizontally from the top of a cliff and eventually hits the ground below. A second stone is dropped from rest
xeze [42]

Answer and Explanation:

As per the question:

When the stone is thrown from the cliff top and hits the ground below eventually:

R = v_{o}\sqrt{\frac{2H}{g}}

where

v_{o} = initial velocity

H = height

g = acceleration due to gravity

R = horizontal Range

Now,

(a) Displacement of the stone is given by the horizontal range:

R = v_{o}\sqrt{\frac{2H}{g}}

where

v_{o} = initial velocity

H = height

g = acceleration due to gravity

R = horizontal Range

(b) Speed just prior to the impact is given by the third equation of motion:

v = \sqrt{v_{o}^{2} + 2gH}

where

v = final velocity

(c) Time of flight is given by the second eqn of motion where the initial velocity is considered to be 0 then:

H = v_{o}T + \frac{1}{2}gT^{2}

H = 0.T + \frac{1}{2}gT^{2}

T = \sqrt{\frac{2H}{g}

3 0
3 years ago
True or False A goal of humanist psychologists today is to help people reach their full potential.
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8 0
4 years ago
Determine the inductance L of a 0.65-m-long air-filled solenoid 3.2 cm in diameter containing 8400 loops.
den301095 [7]

Answer:

The inductance is  L  = 0.1097 \ H

Explanation:

From the question we are told that

  The  length is  l  =  0.65 \ m

   The  diameter is  d =  3.2 cm  = 0.032 \ m

    The  number of loops is  N  =  8400

Generally the radius is evaluated as

       r = \frac{ 0.032 }{2}  =  0.016 \ m

The  inductance is mathematically represented as

      L  =  \frac{ \mu_o  *  N^2  * A }{ l }

Here \mu_o is the permeability of free space with value  \mu_o   = 4\pi * 10^{-7} N/A^2

A is the cross-sectional area which is mathematically evaluated as

             A =  \pi  r^2

=>        A =  3.142 *  (0.016)^2

=>        A =  0.000804 \ m^2

 =>  L  =  \frac{   4\pi * 10^{-7} *  8400^2  * 0.000804  }{ 0.65 }

=>    L  = 0.1097 \ H

5 0
3 years ago
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