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irga5000 [103]
3 years ago
8

What is the density of mass is equal to 22 grams volume is equal to 22 centimeters cubed​

Physics
1 answer:
IgorLugansk [536]3 years ago
5 0

Because both have the exact number of occupants of density

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An airplane leaves New York to fly to Boston it travels 1000 KM in two hours what is the average speed of the airplane
Korolek [52]

Answer: 500 KM per hour

Explanation:

5 0
3 years ago
In the absence of air resistance two balls are thrown upward from the same launch point. Ball a rises to a maximum height above
diamong [38]

Answer:

Va is two times greater than Vb

Explanation:

The maximum height reached by the balls are:

Ymax = \frac{Vo^2}{2g}

Since we are told that Ya = 4Yb:

Ya =  \frac{Va^2}{2g} = 4* Yb = 4 * \frac{Vb^2}{2g}

Simplifying the equation:

Va^2 = 4*Vb^2

Va = 2*Vb

5 0
3 years ago
I rent a small high pressure water sprayer to clean the outside of my house. The sprayer works like a super soaker with a hose b
viva [34]

Answer:

1. 80,000 Pa

2. 11.3 m/s

3. 12.5 m/s

Explanation:

<u>Question 1</u>

Pressure, P=hg\rho

Where h is the height that water is to reach, g is gravitational constant and \rho is the density, in this case, we assume \rho of pure water as 1000 Kg/m^3

Assuming g=10 m/s^{2}

P=8*10*1000=80000 Pa

<u>Question 2</u>

Pressure can also be found by the formula

P=0.5v^{2}\rho where v is the velocity

Equating the new formula of pressure to the formula used in question 1 above

P=0.5v^{2}\rho=hg\rho

Notice that \rho is common hence

0.5v^{2}=hg

Making V the subject of the formula

v^{2}=2hg

v=\sqrt 2hg

In this case, h=8-1.6=6.4m and taking g as 10 m/s^{2}

v=\sqrt 2*10*6.4=11.3137085  m/s

Rounding off to 1 decimal place

v=11.3 m/s

<u>Question 3</u>

As already illustrated

v=\sqrt 2hg

Taking g as 9.8 and h now is 8m

v=\sqrt 2*8*9.8

v=12.52198067

Rounding off to 1 decimal place

v=12.5 m/s

6 0
3 years ago
The state of matter that keeps its shape and volume when it is placed in different containers
FinnZ [79.3K]
A solid is the only state of matter that keeps it shape and volume when placed in different containments
6 0
4 years ago
An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only
vlabodo [156]

Answer:

15.8m/s

Explanation:

This problem can be solved by taking into account the conservation of the momentum. In this case the momentum of the astronaut and the bag of tools must equal the momentum of the astronaut and the bag of tool after the astronaut throws the bag.

Hence, we have

p_{before}=p_{after}\\(m_{a}+m_{b})v=m_{a}v_{a}+m_{b}v_{b}

where ma and va are the mass and velocity of the astronaut, mb and vb are the mass and velocity of the bag, after the astronaut throw the bag. The velocity v is the velocity where the astronaut has the bag of tool

By taking into account that the velocity of the astronaut must be zero to keep him near of the space station, we have that vb = 0.

Thus

(124 + 19.0)2.10=19.0v_{b}\\v_{b}=\frac{300.3}{19.0}=15.8m/s

8 0
3 years ago
Read 2 more answers
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