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3 years ago

How does mass and force affect the motion of an object?

Physics

2 answers:

liberstina [14]3 years ago

8 0

My teacher always said in science The greater the mass of an object, the more inertia it has so this is the awnser

djyliett [7]3 years ago

4 0

The greater the mass of an object, the more inertia it has, so the object resists changes to its motion better.

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He has 54 cds and every box has 9 cds.how many boxes are in 54 cds?

Gemiola [76]

Solution:
54 / 9 = 6 boxes.

6 0

3 years ago

45. An object with a mass of 25 kg accelerates east at a rate of 7 m/s? What fiet force is acting on the object?

ZanzabumX [31]

Answer:

According to newton's second law of motion F=ma so

Explanation:

Data:-M=25kg ,a=7m/s² F=? ,solution:-F=ma ,F=25×7=175kgm/s² or N

6 0

4 years ago

The wavelength of red helium-neon laser light in air is 632.8 nm.

e-lub [12.9K]

(a) $4.74\cdot 10^14 Hz$

The frequency of an electromagnetic wave is given by:

$f=\frac{c}{\lambda}$

where

$c=3.0\cdot 10^8 m/s$ is the speed of the wave in a vacuum (speed of light)

$\lambda$ is the wavelength

In this problem, we have laser light with wavelength

$\lambda=632.8 nm=6.33\cdot 10^{-7} m$ . Substituting into the formula, we find its frequency:

$f=\frac{3.0\cdot 10^8 m/s}{6.33\cdot 10^{-7} m}=4.74\cdot 10^14 Hz$

(b) 427.6 nm

The wavelength of an electromagnetic wave in a medium is given by:

$\lambda=\frac{\lambda_0}{n}$

where

$\lambda_0$ is the original wavelength in a vacuum (approximately equal to that in air)

$n$ is the index of refraction of the medium

In this problem, we have

$\lambda_0=632.8 nm$

n = 1.48 (index of refraction of glass)

Substituting into the formula,

$\lambda=\frac{632.8 nm}{1.48}=427.6 nm$

(c) $2.03\cdot 10^8 m/s$

The speed of an electromagnetic wave in a medium is

$v=\frac{c}{n}$

where c is the speed of light in a vacuum and n is the refractive index of the medium.

Since in this problem n=1.48, we find

$v=\frac{3\cdot 10^8 m/s}{1.48}=2.03\cdot 10^8 m/s$

3 0

4 years ago

As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air

MArishka [77]

This question involves the concepts of work done, pressure, and temperature.

The work done per mol of the air is "-724.71 J/mol".

Using the given formula for work done:

$W=RTln\frac{P_1}{P_2}$

where,

W = work done per mol = ?

R = universal gas constant = 8.314 J/mol.k

T = absolute temperature = 30°C + 273 = 303 k

P₁ = initial pressure = 30 KPa

P₂ = final pressure = 40 KPa

Therefore,

$W= (8.314\ J/mol.k)(303\ k)ln\frac{30\ KPa}{40\ KPa}\\$

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Learn more about pressure here:

brainly.com/question/23358029?referrer=searchResults

7 0

3 years ago

Describe the relationship between joules, meters, and newtons

Naily [24]

Newton is a unit of force. Joules is an amount of work which is equal to the force times distance, or newton meters. So the product of newtons and meters makes joules.

5 0

3 years ago