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3 years ago

Describe how Newton’s third law applies to the box and the table.

Physics

2 answers:

Pepsi [2]3 years ago

5 0

Answer:

An object at rest remains at rest, an object in motion remains in motion at a constant velocity unless affected by external forces. So the box will remain at rest since the acceleration is zero

Snowcat [4.5K]3 years ago

3 0

Answer:

the box has vertical force on the table

Explanation:

There can be no single isolated force, for every action there must be a force of reaction of ingual magnitude and direction, but in the opposite direction

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What is hypothesis testing

Stells [14]

Hypothesis testing is basically testing the results of a experiment to see weather your results are valid or not.

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3 years ago

Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflec

tatiyna

'The normal is a line perpendicular to the surface of the mirror'.This is the correct statement that corrects an error on the site.

<h3>What is the law of reflection?</h3>

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

Hence 'The normal is a line perpendicular to the surface of the mirror'.This is the correct statement that corrects an error on the site

To learn more about the law of reflection refer to the link;

brainly.com/question/12029226

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2 years ago

Read 2 more answers

Why do you choose MCB in place of a fuse？

astraxan [27]

It protects the electrical appliance and the person from electrical shocks/faults.

Hope it Helped!

3 0

3 years ago

A television remote control uses infrared light with a wavelength of 940 nm. What is the frequency of the light?

Ronch [10]

Answer:

Frequency = 3.19 * 10^14 Hz or 1/s

Explanation:

Relationship b/w frequency and wavelength can be expressed as:

C = wavelength * frequency, where c is speed of light in vacuum which is 3.0*10^8 m/s.

Now simply input value (but before that convert wavelength into meters to match the units, you do this by multiply it by 10^-9 so it will be 940*10^-9)

3.0 * 10^8 = Frequency * 940 x 10^-9

Frequency = 3.19 * 10^14 Hz or 1/s

5 0

3 years ago

A block, M1=10kg, slides down a smooth, curved incline of height 5m. It collides elastically with another block, M2=5kg, which i

erma4kov [3.2K]

Answer:

2.86 m

Explanation:

Given:

M₁ = 10 kg

M₂ = 5 kg

$\mu_k$ = 0.5

height, h = 5 m

distance traveled, s = 2 m

spring constant, k = 250 N/m

now,

the initial velocity of the first block as it approaches the second block

u₁ = √(2 × g × h)

u₁ = √(2 × 9.8 × 5)

u₁ = 9.89 m/s

let the velocity of second ball be v₂

now from the conservation of momentum, we have

M₁ × u₁ = M₂ × v₂

on substituting the values, we get

10 × 9.89 = 5 × v₂

v₂ = 19.79 m/s

now,

let the velocity of mass 2 when it reaches the spring be v₃

from the work energy theorem, we have

Work done by the friction force = change in kinetic energy of the mass 2

$0.5\times5\times9.8\times2 = \frac{1}{2}\times5\times( v_3^2-19.79^2)$

v₃ = 20.27 m/s

now, let the spring is compressed by the distance 'x'

therefore, from the conservation of energy

we have

Energy of the spring = Kinetic energy of the mass 2

$\frac{1}{2}kx^2=\frac{1}{2}mv_3^2$

on substituting the values, we get

$\frac{1}{2}\times250\times x^2=\frac{1}{2}\times5\times20.27^2$

x = 2.86 m

8 0

3 years ago