Answer:
t=L/
Explanation:
<u>solution:</u>
Let E be an observer, and B a second observer traveling with velocity
as measured by E. If E measures the velocity of an object A as
then B will measure A velocity as
=
-
Applied here,
the walkway (W) and the man (M) are moving relative to Earth (E}, the velocity of the man relative to the moving walkway is
=
-
,

The time required for the woman, traveling at constant speed
relative to the ground, to travel distance L relative to the ground is
:
t=L/
Power = work/time = (Force times distance)/time
= (30N *10.0m)/5.00s = 300/5 = 60 Watts
Answer:
a = 16 m/s²
General Formulas and Concepts:
<u>Dynamics</u>
Newton's Law of Motions
- Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
- Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
- Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u>
</u>
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] F = 22000 N
[Given] m = 1375 kg
[Solve] a
<u>Step 2: Find Acceleration</u>
- Substitute in variables [Newton's 2nd Law of Motion]: 22000 N = (1375 kg)a
- Isolate <em>a</em>: 16 m/s² = a
- Rewrite: a = 16 m/s²
Answer:
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