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MAVERICK [17]
2 years ago
6

If x^9/x^7 = 49, what is the value of x^4/x^2?

Mathematics
1 answer:
8090 [49]2 years ago
6 0

Answer:

x^4/x^2 = 49

Step-by-step explanation:

First, you want to simplify the first response.

x^9/x^7 = 49

9 - 7 = 2

x^2 = 49

x = 7

You would then simplify the second equation

x^4/x^2 = ?

4 - 2 = 2

x^2 = ?

Substitute in the 7

7^2 = ?

49 = ?

x^4/x^2 = 49

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Answer:

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Step-by-step explanation:

12c+2d=48g

2d=48g-12c

d=24g-6c

7 0
3 years ago
How did the graph of f(x) = x^2 and g(x) = 3/4 x^2 relate?
nirvana33 [79]

g(x) = \frac{3}{4} f(x) or g(x) is 3/4 times of f(x) , F(x) and g(x) have common solution or intersecting point in the graph parabola at x=0 i.e. in origin and x = \frac {4}{3}.

<u>Step-by-step explanation:</u>

We have a function f(x) = x^{2} and another function , g(x) = \frac{3}{4} x^{2}. In the graph of y = x^{2} , the point (0, 0) is called the vertex. The vertex is the minimum point in a parabola that opens upward. In a parabola that opens downward, the vertex is the maximum point.

Graphing y = (x - h)2 + k , where h = 0 & k = 0

Function g(x) can be formed with compression in function f(x) by a factor of 3/4 , i.e. g(x) = \frac{3}{4} f(x) or g(x) is 3/4 times of f(x).Domain and range of f(x) and g(x) are same ! Although structure of both functions is same the only difference is g(x) is compressed vertically by a factor 3/4. Both are graph of a parabola with vertex at (0,0). Also, F(x) and g(x) have common solution or intersecting point at x=0 i.e. in origin.

7 0
3 years ago
I need help on this one??!??
bekas [8.4K]

Answer:

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Step-by-step explanation:

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3 years ago
[(-33) + 46 + 68] - |15 - 61|
Gemiola [76]

Answer:

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Step-by-step explanation:

[(-33) + 46 + 68] - (15 - 61)

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127

6 0
3 years ago
I need help with :: <br> 3x + 4 = 5x - 10
lara31 [8.8K]
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2 years ago
Read 2 more answers
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