Question

Oordinates of point that divides the join of A (-6, 3) & B (5, -2) in ratio 2 : 3 externally _________.

Answer 1

Answer:

C(x,y) = (-28,13)

Step-by-step explanation:

If co-ordinates of points A(x1,y1) and (x2,y2) and C is the external point that divides the line AB in ratio m:n then,

$C (x,y) = \frac{mx_2-nx_1}{m-n} , \frac{my_2-ny_1}{m-n}$

Given: A (-6, 3) & B (5, -2) in ratio 2 : 3

Substituting these values in above formula to C(x,y)

C (x,y) = \frac{2\times5-3(-6)}{2-3} , \frac{2(-2)-3(3)}{2-3}

Solving we get

C(x,y) = (-28,13)