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nikdorinn [45]
2 years ago
15

The terminal ray of a 300° angle lies in the This angle measures i radians. quadrant.

Mathematics
2 answers:
Stells [14]2 years ago
6 0

Answer:

ill help

Step-by-step explanation:

NARA [144]2 years ago
5 0

Answer: fourth

Step-by-step explanation: the terminal ray of a 300 angle lies in the FOURTH quarter.

This angle measures (5/3) radians.

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The ratio of pencils to erasers is 4:1 if there are 20 pencils how many erasers are there?
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It is 5 because you have to multiply by 5 by 4 and get 20 when you multiply by 5×1 and get 5
7 0
3 years ago
Jim's soccer team is making fruit baskets for a fundraiser. They have 88 peaches, 60 bananas, and 54 kiwis to use. If each baske
cluponka [151]

The greatest number of fruit baskets they can make is 2 with each one having 44 peaches, 30 bananas and 27 kiwis

<h3><u>Solution:</u></h3>

Jim’s fruit basket has 88 peaches, 60 bananas and 54 Kiwis to  use.

If each basket have same number of each type, we have to determine the greatest number of fruit baskets they can make  

We need to find greatest common factor of 88, 60 and 54

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

<em><u>Greatest common factor of 88, 60 and 54:</u></em>

The factors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 88 are: 1, 2, 4, 8, 11, 22, 44, 88

Then the greatest common factor is 2

On dividing the number of fruits by 2 we get

\begin{array}{l}{\text { Apples in each basket }=\frac{88}{2}=44} \\\\ {\text { Bananas in each basket }=\frac{60}{2}=30} \\\\ {\text { Kiwis in each basket }=\frac{54}{2}=27}\end{array}

Hence, there can be 2 basket with each one having 44 peaches, 30 bananas and 27 kiwis

6 0
3 years ago
What is the equation of the line that is parallel to the
o-na [289]

Answer:

y=x+3

Step-by-step explanation:

7 0
2 years ago
Given f(x) = 4x^2 + 19x - 5 and g(x) = 4x^2 - x what is (f/g)(x)?
Free_Kalibri [48]

( \frac{f}{g} )(x) =  \frac{4 {x}^{2}  + 19x - 5}{4 {x}^{2}  - x}  =  \frac{(4x - 1)(x + 5)}{x(4x - 1)}  =  \frac{x + 5}{x}

3 0
3 years ago
Read 2 more answers
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
3 years ago
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