What is an equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15?
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A right triangle is a special triangle that has a right angle. In this case, we have to write a system of inequalities that defines a shaded region that looks like a right triangle. First of all, let's say that at the origin the triangle will have a right angle. To do so, we'd need to set:
So the shaded region in this first part will be the First Quadrant as indicated in the first figure below. So if the opposite side lies on the x-axis the adjacent side will lie on the y-axis or if the adjacent side lies on the x-axis the opposite side will lie on the y-axis. Everything is ok up to this point. We just need to define the hypotenuse, so we'd need to define a line. In order to have a right triangle, we need a line with negative slope and positive y-intercept shaded under the line. So, this inequality could be:
Finally, the system of inequalities would be:
And the final shaded region is the one shown in the second figure.
<h2>Learn more:</h2>Inequalities: brainly.com/question/2486051
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