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2 years ago

Example of propertional relationship

Mathematics

1 answer:

Leokris [45]2 years ago

3 0

Answer:

1/2 and 6/12 have a proportional relationship, which means they are the same.

Step-by-step explanation:

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Evaluate the expression \dfrac{5\cdot x^3}{x^2} x 2 5⋅x 3 start fraction, 5, dot, x, cubed, divided by, x, squared, end fracti

Fantom [35]

Answer:

Step-by-step explanation:

Given the expression:

(5 * x³) / x² ; for x = 2

Simplifying (5 * x³) / x²

5 * x^(3-2)

5 * x^1

= 5x

For x = 2

5x = 5*2 = 10

8 0

2 years ago

The image of the point (3, -4) under a translation is (0, –5). Find the coordinatesof the image of the point (8,7) under the sam

Sav [38]

We will have the following:

*First: We determine the translation rule:

We have that the point went from (3, -4) to (0, -5), thus the translation rule would be:

$(x,y)\to(x-3,x-1)$

Second: We apply the translation rule to the other point to determine it's image, that is:

$(8,7)\to(8-3,7-1)\to(5,6)$

So, the image of the second point is (5, 6).

6 0

1 year ago

If m ≤ f(x) ≤ M for a ≤ x ≤ b, where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then m

Korvikt [17]

Answer:

The final integration in the given limits will be 89.876

6 0

2 years ago

In a continuous series, mean(x) = 80, assumed mean(A) = 60 and<br>EF=40 then find the value of EFd.

Aneli [31]

Using the given information, the value of Σfd is 800

<h3>Calculating mean using Assumed mean </h3>

From the question, we are to determine the value of Σfd

The formula for mean, using the assumed mean method is given by

$\bar x = A + \frac{\sum fd}{\sum f}$

Where $\bar x$ is the mean

A is the assumed mean

From the given information,

$\bar x = 80$

$A = 60$

$\sum f = 40$

Putting the parameters into the equation, we get

$80 = 60 + \frac{\sum fd}{40}$

$80-60 = \frac{\sum fd}{40}$

$20 = \frac{\sum fd}{40}$

$\sum fd = 20 \times 40$

$\sum fd = 800$

Hence, the value of Σfd is 800

Learn more on Mean here: brainly.com/question/20118982

#SPJ1

8 0

2 years ago

Use the graph below to answer the question that follows:

snow_lady [41]

Answer:

D) Amplitude: 2; period: π; midline: y = 1

Step-by-step explanation:

The question is much more easily answered from the graph than from the description of the graph.

The amplitude is the extent of the peak above the midline (2), or half the peak-to-peak value (4/2=2). The midline is the line halfway between the peaks (1). The period is the horizontal distance between peaks of the same polarity (π).

7 0

3 years ago

Read 2 more answers