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Vinvika [58]
2 years ago
8

What interval notation represents the data graphed below?

Mathematics
1 answer:
Aliun [14]2 years ago
6 0

Answer: Choice D

(-\infty, -2) \cup [4, \infty)

=====================================================

Explanation:

The left portion is the interval (-∞, -2)

This is a shorthand way of saying -\infty < x < -2

The curved parenthesis says "do not include this endpoint as part of the solution set". Note the open hole at x = -2 in the diagram.

In contrast, the value x = 4 is included (due to the filled in circle), so we use a square bracket for this endpoint. Therefore, the right-hand portion is represented by [4, ∞) which translates to 4 \le x < \infty

Negative and positive infinity will always use a parenthesis, and never a square bracket. This is because we can only approach infinity but never reach it, so we cannot include it as an endpoint.

All of this builds up to the full interval notation to be (-\infty, -2) \cup [4, \infty)

The only square bracket is near the 4; everything else is a curved parenthesis. This is why choice D is the final answer.

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Step-by-step explanation:

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X=-3<br> A. 64<br> B. 8<br> C. 4<br> D. 16
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8 0
2 years ago
Factor x2 + 16 completely.
Dmitry_Shevchenko [17]
<h3>Answer:</h3>

Prime

<h3>Solution:</h3>
  • Let's factor this expression.
  • x^2+16
  • The expression is prime.
  • Let's see why all the other options are wrong.
  • Option A) (x+4)(x+4)
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Hope it helps.

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6 0
2 years ago
Read 2 more answers
No files or links please!
BaLLatris [955]

Answer: there you go

Step-by-step explanation:

5 0
3 years ago
Select the correct answer.
Volgvan

Answer:

B

Step-by-step explanation:

If C is the correct answer and if the final result is multiplied out, where does the minus sign in a^4 - b^4 come from? All pluses don't make a minus. A is incorrect.

If D is correct, then a^2 - b^2 should be further factored producing a different kind of answer, like (a + b)^2(c-d)^2 which is not the same as a^4 - b^4. So D is not correct.

The first step in factoring a^4 - b^4 is (a^2 + b^2)(a^2 - b^2) A doesn't lead you anywhere. A is incorrect. The answer must be B.

a^4 - b^4 = (a^2 -  b^2)(a^2 + b^2)  The first term factors.

a4 - b^4 = (a + b)(a - b) (a^2 +b^2)

4 0
3 years ago
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