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3 years ago

11

I WILL GIVE BRAINLIEST I NEED HELP ASAP PLEASE!!!

1 answer:

Anit [1.1K]3 years ago

4 0

Answer:

20 ft

Step-by-step explanation:

If you count how many unit’s there is on the picture then multiply by 2, you get 20

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The image below is a triangle drawn inside a circle with center O: A triangle is shown inscribed inside a circle. The leg of the

Elis [28]

The area of a circle is given in terms of its radius by

A = π · r²

Your circle has r=4 (half the diameter) and you want π=3.14. Using these values in the formula gives

A = 3.14 · 4²

This matches your first selection

3.14 · 4²

<em> MARK AS BRAINLIEST</em>

7 0

3 years ago

Evaluate.<br> 25/5+7-(4x3)

navik [9.2K]

Using PEMDAS, we know that we must solve what’s in the perentheses first so: 25/5 + 7 - (4x3) = 25/5 + 7-12. Next, we simplify 25/5 because that is division so now it is 5+7-12. Now you add 7 to 5 to get 12 and then subtract 12 so your answer is now zero.

7 0

2 years ago

Given that HOP is similar to TAG, which of the following statements must be true? Check all that apply. A. sin T = sin H B. cos

Tju [1.3M]

Pls. see attachment.

3 0

3 years ago

Read 2 more answers

In a complete sentence, describe the positions of these numbers on the number line in relation to each other. Then, write an ine

Tasya [4]

Answer:

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7 0

2 years ago

Someeee one?????????????????

Ad libitum [116K]

Answer:

Option B) $a_{n} = 2\cdot 4^{n-1}$

Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

$a_{n} = a_{1}\cdot r^{n-1}$

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

$r=\frac{8}{2} = 4$

You can try other consecutive numbers too, you will get the same common ratio

$r=\frac{32}{8} = 4$

$r=\frac{128}{32} = 4$

So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

$a_{n} = 2\cdot 4^{n-1}$

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

$a_{n} = 2\cdot 4^{n-1}$

Lets find out the 2nd term

Substitute n = 2

$a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8$

Lets find out the 3rd term

Substitute n = 3

$a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32$

Lets find out the 4th term

Substitute n = 4

$a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128$

Lets find out the 5th term

Substitute n = 5

$a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512$

Hence, we are getting correct results!

6 0

3 years ago