Which is the other endpoint of a line segment with one endpoint at (-2, 5) and midpoint at (3, 1)?
2 answers:
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F(x) = ln(x² - 12x)
The derivative is
f(x) is undefined when x² - 12x = x(x - 12) = 0
That is, when x = 0 or x = 12.
Therefore the domain is (-∞, 0)∪(0,12)∪(12, ∞)
Answer:
The derivative is
The domain is
(-∞, 0)∪(0, 12)∪(12,∞)
The derivative is
f(x) is undefined when x² - 12x = x(x - 12) = 0
That is, when x = 0 or x = 12.
Therefore the domain is (-∞, 0)∪(0,12)∪(12, ∞)
Answer:
The derivative is
The domain is
(-∞, 0)∪(0, 12)∪(12,∞)