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Dmitry [639]
3 years ago
7

Please help quickly this is like the last answer for a test so please help quickly

Mathematics
1 answer:
Ganezh [65]3 years ago
3 0

Answer: b

its a 3.5 degree angle it is b

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
What is 1.59 in word form
Amanda [17]
One and fifty nine hundredths.

Be careful not to say "hundreds" as that's 100, not 0.01

Hope this helps!
4 0
3 years ago
Read 2 more answers
Please help!!! ITS URGENT!1
tatiyna

Answer:

answer was 3)

Step-by-step explanation:

Because function was star with 1,2,3,4,

6 0
3 years ago
Pentagon DEFGH is translated 4 units to the right to create pentagon UVXYZ. DE is 5cm long. What is the length of UV?
Semmy [17]
If a shape is translated (has it's vertex' coordinates moved/changed), then it retains its original values but just has different vertex coordinates.

Thus since DE is equal to UV, then,

DE = UV; substitution:
5=5
3 0
3 years ago
Factor the following Polynomials 2x2 + 5x + 2
Leokris [45]

Answer:

Step-by-step explanation:

Find the multiples of 2x^2 and 2

for 2x^ you get 2,1 but they need to have x  to get x^2 so; (2x and x)=2x^2

for 2 you get 2,1 (2x1)=2

Because your equation has a 5x and no negatives you know that your factors need to be positive.

(2x+1)(x+2)

when you multiply these you get

2x^2+4x+x+2 (remember 2x multiplies with everything inside (x+2) = 2x^2+4) and so on for the x (x+2) =x+2 )

Then you combine like terms 4x+x=5x

and those are the only like terms available and you get

2x^2+5x+2

Hope it helped

3 0
2 years ago
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