Answer:
the solution of the system is:
x = 1 and y = 2.
Step-by-step explanation:
I suppose that we want to solve the equation:
-6*x + 6*y = 6
6*x + 3*y = 12
To solve this, we first need to isolate one of the variables in one of the equations.
Let's isolate y in the first equation:
6*y = 6 + 6*x
y = (6 + 6*x)/6
y = 6/6 + (6*x)/6
y = 1 + x
Now we can replace this in the other equation:
6*x + 3*(1 + x) = 12
6*x + 3 + 3*x = 12
9*x + 3 = 12
9*x = 12 - 3 = 9
x = 9/9 = 1
Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.
y = 1 + (1) = 2
Then the solution of the system is:
x = 1 and y = 2.
Answer:
-2x + 4y = 16.
Step-by-step explanation:
y = 2/4x+ 4 Multiply through by 4:
4y = 2x + 16
-2x + 4y = 16 is the standard form.
27j-6=14j+7
Subtract 14j from both sides
27j-6-14j=14j+7-14j
13j-6=7
Add 6 to both sides
13j-6+6=7+6
13j=13
Divide both sides by 13
13j/13=13/13
j=1
I hope that's help !
The integers are -8 and -6.
To find these, first assume that the first integer is x. Then, because it is an even integer, assume the next is x + 2. Now we can write an equation to solve.
Tripling the greater = subtracting 10 from the lesser
3(x + 2) = x - 10 ----> Distribute the 3
3x + 6 = x - 10 ----> Subtract x from both sides
2x + 6 = -10 ----> Subtract 6 from both sides
2x = -16 ----> Divide both sides by 2
x = -8
Which is the first integer. We then can determine that the second one, which is two higher than the first, would be -6.
Answer:
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