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nikitadnepr [17]
3 years ago
10

Plz help me this was due yestrday but my mom wont let me do it

Mathematics
1 answer:
AURORKA [14]3 years ago
8 0

Answer:

120

Step-by-step explanation:

z=8 w=8

7(8)=56

8(8)=64

56+64=120

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Paula's house is assessed at $213,000, and her property tax rate is 2.9%. How
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Answer:A

Step-by-step explanation:

She is taxed at a rate of 2.9%, so each year she is taxed 213000 * 2.9% . calculating this, we find that every year, she must pay 6177 in taxes. However, we need the amount in a month, so we divide by 12, to get 6177/12= 514.75, or A

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Which number has the least value?<br><br> 1. 2 3/4<br> 2. 5/2<br> 3. 2.62<br> 4. 245%
Leni [432]
The number with the least value is 2.62
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3 years ago
Which of the following is the graph of y = 5?
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Slope: 0
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3. You want to have $4000 in your savings account after 2 years. Find the amount you should deposit for each of the situations d
pychu [463]

Answer:

Part A)

About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}

Where <em>A</em> is the final amount, <em>P</em> is the initial amount, <em>r</em> is the interest rate, <em>n</em> is the number of times compounded per year, and <em>t</em> is the number of years.

To obtain $4000 after two years, let <em>A</em> = 4000 and<em> t</em> = 2.

Because the account pays 3% interest compounded monthly, <em>r</em> = 0.03 and <em>n</em> = 12.

Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

\displaystyle A = Pe^{rt}

Where <em>e</em> is Euler's number.

Hence, let <em>A</em> = 4000, <em>r</em> = 0.04 and <em>t</em> = 2. Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}

In conclusion, about $3692.47 should be deposited.

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Analyze the diagram below and complete the instructions that follow.
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The answer would be D just took test

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