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marin [14]
3 years ago
8

Use graph to answer questions

Mathematics
1 answer:
shutvik [7]3 years ago
3 0

Answer:

\sin(  \alpha )  =   \frac{4}{5}

Step-by-step explanation:

as if we form an imaginary triangle with this line as hypotenuse

we get

  • base = 3 units
  • perpendicular = 4 units

using Pythagoras theorem:-

hyponteuse ² = perpendicular ² + base²

hyp² = 4² + 3²

hyp² = 16 + 9

hyp =  \sqrt{25}

hyp = 5 units

\sin( \theta )   =  \frac{perpendicular}{hypotenuse}  \\  \sin( \theta)  =  \frac{4}{5}

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find f(0) and f(1)

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6 0
3 years ago
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kolbaska11 [484]
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7 0
3 years ago
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Solve for g:<br> 3/16=(-5/4)+g
Musya8 [376]

Answer:

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7 0
3 years ago
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Slav-nsk [51]

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