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3 years ago

Captain America's circular shield has a diameter of 76.2 centimetres. What is the area of his shield?

Mathematics

2 answers:

Sonbull [250]3 years ago

4 0

Step-by-step explanation:

I I should just be 76.2 cm for the whole area

Alex Ar [27]3 years ago

3 0

Answer:

4560.37

Step-by-step explanation:

A= 1 /4 x π x 76.2²

Brainliest?????

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Find the ratio a:b, if 2a−b/6 = b/3

Tom [10]

Answer:

a:b = 2

Step-by-step explanation:

Here we need to operate with terms in order to arrive to a ratio a:b (or a/b).

We have:

2a−b/6 = b/3

Lets sum b/6 in both sides:

2a−b/6 + b/6 = b/3 + b/6

2a = b/3 + b/6

Now, we can multiply and divide b/3 by 2 to make a 6 appear on the denominator and sum it with b/6, this is, use common denominator:

2a = b/3*(2/2) + b/6

2a = 2b/6 + b/6

2a = 3b/6

2a = b/2, as 3/6 = 1/2

Now lets divide both sides by b to make an a/b appear:

2a/b = (b/2)/b

2a/b = 1/2

Finally, multiply both sides by (1/2) or divide by 2:

(2a/b)/2 = 2

a/b = 2

This is, a is twice as b. If b is 1 so a is 2; if b is 45 so a is 90, and so on.

7 0

3 years ago

Which of the following points is a solution of y ≤ -|x| - 1?<br><br> (-1, -3)<br> (0, 0)<br> (1, -1)

alexdok [17]

Y + 1 $\leq$ -|x|
-y - 1 $\geq$ |x|
-(-y - 1) $\leq$ x $\leq$ -y - 1
(0, 0)

Answer: B).

3 0

3 years ago

Read 2 more answers

What is a correct congruence statement for the triangles shown? Enter your answer in the box. △QDJ≅△ A triangle Q D J. The b

almond37 [142]

Answer: The correct congruence statement is $\triangle QDJ\cong \triangle MCW$ .

Explanation:

It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.

The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.

Draw two triangles according to the given information.

From the figure it is noticed that

$QD\cong MC$