James needs to wrap a Christmas
1 answer:
You might be interested in
The graphs of f(x) and g(x) are transformed function from the function y = x^2
The set of inequalities do not have a solution
<h3>How to modify the graphs</h3>
From the graph, we have:
and
To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.
To derive y > x^2 + 2, we perform the following transformation on the function g(x)
- Shift the function g(x) down by 2 units
- Reflect across the x-axis
- Shift the function g(x) down by 3 units
- Change the equality sign in the function g(x) to greater than
The inequalities of the graphs become
y < x^2 - 3 and y > x^2 + 2
From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.
Hence, the set of inequalities do not have a solution
Read more about inequalities at:
Answer:
let required no be x
by doing crisscrossed multiplication
42=7x
dividing both side by 7
6=x
therefore x=6
therefore value of remaining no.is 6