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denis-greek [22]
2 years ago
11

Which is greater, (1/2)⁴² or (1/2)⁴⁵? Why?​

Mathematics
1 answer:
weqwewe [10]2 years ago
8 0

Answer:

1/2^42 because the 45 will be dividing it b half 3 more times

Step-by-step explanation:

You might be interested in
the numbers of girls in the choir is 4 times the number of boys in the choir .the total number of students is 60..how many girls
Inessa05 [86]
First, make up some variables to represent the number of Girls and Boys in the choir.  

B = number of boys
G = number of girls

You know that there are 4 times as many girls in the choir as boys.  Therefore, the equation you can write is:
\frac{B}{G} =  \frac{1}{4}

If you cross-multiply, then you get the simplified equation:
G = 4B

Intuitively this makes sense since if you multiplied the number of boys in the class by 4, that would be equal to the number of girls you have.

Now, we know that the total class size is 60. So girls plus boys equals 60:
G+B = 60

To solve the equation, replace the G in this equation with the replacement you found before, 4B.
G + B = 60 -->
4B + B = 60 -->
5B = 60 -->
B = 12

However, you are trying to find the number of girls, so plug the answer back into your equation.
G + B = 60 -->
G + 12 = 60 -->
G + 12 -12 = 60 - 12 -->
G = 48

The number of girls you have is 48.

6 0
3 years ago
Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!! FINALS!
GenaCL600 [577]
Factor completely x³ + 6x² - 3x – 18
- 6 + 6( - 6)^{2}  - 3( - 6) - 18 \\  - 6 +6 \times 6 ^{2}  + 18 - 18 \\  - 6 + 6 ^{3}  + 18 - 18 \\  - 6 + 216 \\ 210
with a root of x = -6

the answer is 210


3 0
3 years ago
Dustin is buying carpet for the living room. How many square feet of carpet will he need to buy?
rusak2 [61]

Complete Question:

Dustin is buying carpet for the living room. If the length of the room is 21 ft and the width

is 11 ft, how many square feet of carpet does he need to buy?

Answer:

231 ft²

Step-by-step explanation:

==>GIVEN:

Length of room (L) = 21 ft

Width of room (W) = 11 ft

==>REQUIRED:

Square feet of carpet to be bought = area of the rectangular room

==>SOLUTION:

The room to be covered with carpet is rectangular in shape. In order to ascertain the square feet of carpet to be bought, we need to calculate the area of the room by using the formula for area of rectangle.

Thus, area of rectangle (A) = Length (L) × Width (W)

A = 21 × 11

A = 231 ft²

Square feet of carpet to be bought = 231 ft²

5 0
3 years ago
25,553,552 find the digit in the hundred thousands place. Which digit has 1/1000 the value of this digit?
Len [333]
25,*55**3,552
*is the digit in the hundred thousand place
**is the digit that has 1/1000 the value of the digit.
(*) indicates the number after the *.
I doubled check this work, but I will update comment with a triple check
6 0
3 years ago
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