The distance formula is given by:
![\begin{gathered} d=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ or \\ d=\sqrt[]{|x2-x1|^2+|y2-y1|^2}_{} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%3D%5Csqrt%5B%5D%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D%20%5C%5C%20or%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B%7Cx2-x1%7C%5E2%2B%7Cy2-y1%7C%5E2%7D_%7B%7D%20%5Cend%7Bgathered%7D)
8(3y+11x) Would be your answer my friend
Answer:
3*5^6 (3*5 to the power of 6)
Step-by-step explanation:
convert all of the 5's to exponents.
I believe this is the answer, if it is correct, please vote me brainliest!
1/3 of an hour = 20 mins
1/6 * 3/1 = 3/6 = 1/2
Unit rate = 1/2 mile per hour
That inequality can be written as n >= 4
The ">=" represents greater than or equal to. On paper you would just add a horizontal line under the ">" and not include the "="
