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butalik [34]
2 years ago
15

What is the slope of the line?

Mathematics
2 answers:
Alexxandr [17]2 years ago
7 0
Ok so the slope of this line is approximately (2,1)
timurjin [86]2 years ago
4 0

Answer:

24'

Step-by-step explanation:

the slop aims for the angle in which the 78 can go in: hope this helps!!

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Greatest to least: 17/20, 19/20, 0.19, 0.24
Yakvenalex [24]
19/20,17/20,0.24,0.19
5 0
3 years ago
How do you translate "fifty-three plus four times c is as much as 21" in an equation
Ulleksa [173]
53+4c=21 \\ \\ 4c=21-53 \\ \\ 4c=-32 \\ \\ c= -\frac{32}{4} \\ \\ \boxed{c=-8}
4 0
3 years ago
A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s
ANTONII [103]
<h2>Hello!</h2>

The answer is:

The ball will hit the ground after t=2.47s

<h2>Why?</h2>

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula.  We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

We are given the function:

h=-5t^{2}-3t+38

Where,

a=-5\\b=-3\\c=38

Then, substituting it into the quadratic equation, we have:

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s

Since negative time does not exists, the ball will hit the ground after:

t=2.473s=2.47s

Have a nice day!

4 0
3 years ago
Read 2 more answers
Please only math geniuses help, what is x+1/5y=-6 in slope intercept form?
weeeeeb [17]
Y=-5x-30. 

Subtract from each side (1/5y=-x-6 )
Then multiply by 5/1 on both sides to get rid of the 1/5 (y=-5x-30)
5 0
3 years ago
Factor the expression using gcf of 45+30​
Korolek [52]

Answer:

15(3+2)

Step-by-step explanation:

45/15=3

30/15=2

3 0
2 years ago
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