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2 years ago

9

Graph the line with slope 1/4 and y intercept -2

2 answers:

andrey2020 [161]2 years ago

8 0

Answer:

y= 1/4x -2

Step-by-step explanation:

Y=mx+b

m is the slope

b is the y intercept

Firdavs [7]2 years ago

3 0

Answer:

$y = \frac{1}{4} + (-2)$

Step-by-step explanation:

Using the formula: y = mx + b

mx = slope

b = y intercept

$y = \frac{1}{4} + (-2)$

Here is what is will look like in a graph:

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If cos 0=2/3, what are the values of sin 0 and tan 0?

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Step-by-step explanation:

● cos O = 2/3

We khow that:

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■■■■■■■■■■■■■■■■■■■■■■■■■

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3 years ago

You have 26 cards, each labeled with a letter of the alphabet. What is the probability of drawing a card that contains one of th

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3 years ago

Read 2 more answers

What’s is part A?? .....

bixtya [17]

Answer:

A. 3

B. 4

C. 1

D. 2

Step-by-step explanation:

Consider all equations:

A. $y=x^2 -6x+8$

This is the equation of parabola with vertex at point

$x_v=\dfrac{-b}{2a}=\dfrac{-(-6)}{2\cdot 1}=3\\ \\y_v=3^2-6\cdot 3+8=9-18+8=-1$

The y-intercept is at point

$x=0\\ \\y=0^2-6\cdot 0+8=8$

Since

$x^2 -6x+8=x^2-4x-2x+8=x(x-4)-2(x-4)=(x-2)(x-4)$ ,

the x-intercepts are at points (2,0) and (4,0)

The leading coefficient is 1 > 0, then the parabola opens upwards.

Hence, the graph of this parabola is 3.

B. $y=(x-6)(x+8)$

This parabola has two x-intercepts at points (6,0) and (-8,0).

The leading coefficient is 1 > 0, then the parabola opens upwards.

The only possible choice is parabola 4.

C. $y=(x-6)^2+8$

This parabola has the vertex at point (6,8), opens upwards, therefore does not intersect the x-axis.

The graph of this parabola is 1.

D. $y=-(x+8)(x-6)$

This parabola has two x-intercepts at points (6,0) and (-8,0).

The leading coefficient is -1 > 0, then the parabola opens downwards.

The only possible choice is parabola 2.

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2 years ago

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