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vova2212 [387]
3 years ago
12

Standard issue passenger license plates in Ohio consist of three letters followed by four numbers. How many standard issue licen

se plates can be produced if there are no restrictions on the letters and numbers?
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

The standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 175760000

Step-by-step explanation:

If there are no restrictions, all numbers and letters are available to be used then. And with no restrictions, every number or letter can appear more than once.

There are 7 spaces available; 3 spaces for letters, 4 spaces for numbers

The different combination of letters and numbers then becomes,

26 × 26 × 26 × 10 × 10 × 10 × 10

This is because, all 26 letters (A to Z) can occupy the first space, the second space and the third space. And all 10 digits (0 to 9) can occupy the fourth space, the fifth space, the sixth space and the seventh space.

So, the standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 26 × 26 × 26 × 10 × 10 × 10 × 10 = 175760000 different standard issue license plates.

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An expression is shown below
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Answer:

B) It is irrational and equal to = 4\sqrt{2}

Step-by-step explanation:

The expression, \sqrt{18} + \sqrt{2} , is an irrational expression because it contains two irrational numbers, \sqrt{18} and \sqrt{2} . Both number are not perfect square. there is no whole number that would be squared that will give you 18 nor 2.

The expression can be equals the following:

\sqrt{18} + \sqrt{2}

= \sqrt{9*2} + \sqrt{2}

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Find the mean of the data in the dot plot below. Make sure to show your work and explain the steps you took in solving the probl
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2 + 3 + 6 + 6 + 7 + 8 + 8 + 8 = 48.

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2 years ago
A filling machine fills bottles of nail polish with amounts that are normallydistributed with mean 18 mL and standard deviation
natulia [17]

Answer:

a. 0.2033 = 20.33% probability that one of the randomly selected bottles is filled with less than 17.5mL of nail polish

b. 0.0019 = 0.19% probability that the average fill of the twelve bottles is more than 17.5mL

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean 18 mL and standard deviation 0.6 mL.

This means that \mu = 18, \sigma = 0.6

a. What is the probability that one of the randomly selected bottles is filled with less than 17.5mL of nail polish?

This is the p-value of Z when X = 17.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{17.5 - 18}{0.6}

Z = -0.83

Z = -0.83 has a p-value of 0.2033

0.2033 = 20.33% probability that one of the randomly selected bottles is filled with less than 17.5mL of nail polish.

b. What is the probability that the average fill of the twelve bottles is more than 17.5mL?

Twelve bottles, so now n = 12, s = \frac{0.6}{\sqrt{12}}

The probability is:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{17.5 - 18}{\frac{0.6}{\sqrt{12}}}

Z = -2.89

Z = -2.89 has a p-value of 0.0019

0.0019 = 0.19% probability that the average fill of the twelve bottles is more than 17.5mL

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2 years ago
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