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kipiarov [429]
3 years ago
13

Greg drew a pair of parallel lines and a line segment next to each other on a chalkboard.

Mathematics
1 answer:
Setler [38]3 years ago
5 0
<span>c.) The parallel lines extend infinitely in both directions, and the line segment has two endpoints.</span>
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IT IS DUE AT 11:59PM. PLEASE HELP!!!!
kaheart [24]

Hello from MrBillDoesMath!

Answer:   b = 4, h = 13

Discussion:

For a triangle with base b" and height "h, the area formula is

A=  (1/2)bh.

In our case A = 26, h = 5b-7, so

26 = (1/2) b (5b-7).  Multiply both sides by 2:

26*2 = b(5b-7) =>

52 = b(5b-7)  =>

52 = 5b^2 - 7b =>           (subtract 52 from both sides)

5b^2 - 7b - 52 = 0.   This factors as follows:

(b - 4) (5 b + 13) = 0        (use quadratic formula to find this)

so b = 4 and h = 5b -7 = 5*4 - 7 = 13


Thank you,

MrB


3 0
2 years ago
Read 2 more answers
Find the distance between each pair of numbers on the number line; then find the coordinate of their midpoint.
quester [9]

Answer:

d = 1 7/24 or 31/24;  midpoint would be half of that,or 31/48

Step-by-step explanation:

Since distance is absolute value, add 2/3 and 5/8 to get the entire distance.  Midpoint is that distance divided by 2.

4 0
2 years ago
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Samantha bought a purse for $72.25. It normally sells for $91.89. How much money did she save?
navik [9.2K]

Answer:

19.64$

Step-by-step explanation:

91.89-72.25

6 0
2 years ago
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HELP ASAP!! 10 points!
masha68 [24]

\dfrac{5}{7}\ of\ 100:\\\\\dfrac{5}{7}\cdot100=\dfrac{5\cdot100}{7}=\dfrac{500}{7}=\dfrac{70+28+2}{7}=\dfrac{70}{7}+\dfrac{28}{7}+\dfrac{2}{7}\\\\=10+4+\dfrac{2}{7}=14\dfrac{2}{7}\\\\\dfrac{2}{7}\ \text{is smaller than}\ \dfrac{1}{2}.\ \text{Therefore}\ 14\dfrac{2}{7}\approx14\\\\Answer:\ \boxed{14}

7 0
3 years ago
Why does it help to rearrange
hichkok12 [17]

Answer:

You don't really need to do it, but it helps you keep things more organized and easier to follow. Imagine if you're doing some multi-variable equation,

2a + 5b + 4d + 3c + b + a + 2d

that looks like a mess, it'll be easier to look at if you put all the similar variables next to each others like this:

a + 2a + b + 5b + 3c + 2d + 4d

(a + 2a) + (b + 5b) + 3c + (2d + 4d)

now you can add them up much easier.

8 0
2 years ago
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