Answer:
Red blood cells and blood plasma do not contain DNA. Red blood cells don't have the DNA containing nucleus and mitochondria. Only white blood cells in blood contain DNA. With blood donation, usually most of the white blood cells are filtered out.
Explanation:
because red blood cells don't have the DNA containing nucleus and mitochondria
Glycine is an amino acid coded by GGA, GGU, GGC, GGG codons. Histidine is an amino acid coded by CAC, or CAU codons. It should be known that the mRNA chain that will be encoded must always have a START codon at the beginning and a STOP codon at the end.
Hydrogen and hydroxide ions
The correct answer is:
A. Will have a intermediate trait 3. Glucose aversion is a genetically-determined incompletely dominant trait
B. Will refuse glucose 2. Glucose aversion is a genetically-determined dominant trait
C. Have a mix of traits depending on experience 4. Glucose aversion is a learned behavior
D. Will accept glucose 1. Glucose aversion is a genetically-determined recessive trait
If we put it simple and say that for example glucose aversion is genetically determinated, with the genotype AA and eating glucose with the genotype aa. The offspring will have Aa genotype (heterozygous). Depending on which phenotype is expressed in heterozygous we can conclude whether the trait is dominant or recessive or due to earned behavior.
1. The answer is Telophase.
This is the last step of mitosis, during which the sister chromatids reach opposite poles. The small nuclear vesicles in the cell begin t reform around the group of chromosomes at each poles. Mitosis is a very important part of cell division because it is the process by which the parent cell gives its DNA to its two daughter cells.
2. The correct answer is 4. The cell would not be able to grow any further
Body cells divide by the process of mitosis; a process in which a body cells undergoes division tow yield two diploid daughter cells, the process enhances growth and development as the cell increase in number by multiplying themselves.
3. The correct answer Telophase II;
In prophase II, the nuclear envelop breaks down the spindle apparatus forms. The nuclear envelope forms around each set of chromosomes and cytokinesis occurs, producing four daughter cells, each with haploid set of chromosomes.
4. The answer is 4. its body cells would have 36 chromosomes and its gametes would have 18 chromosomes. The somatic cells or the body cells are cells that have diploid (two pairs of chromosome) number, while the gametes are formed from the process of meiosis and contains haploid number of chromosomes.
5. The best answer is ; meiosis ; it increases genetic variation, which helps ensure the species will survive. Meiosis is a type of cell division in which a cell (germ-line cells), where a cell divides to yield four daughter cells which are haploid; Meaning they have half the number of chromosomes as the parent cell.
6. The answer is 50 percent. If the dominant allele is Y and the recessive allele; Therefore; the heterozygous will be Yy and the homozygous green color will be yy.
Thus; A cross between heterozygous Yy and the green recessive yy will yield; 50 percent heterozygous and also half homozygous recessive.
7. The correct answer is that One parent was heterozygous for eye color and the other was homozygous with red eyes.
An organism can be homozygous dominant, if it carries two copies of the same dominant allele, or homozygous recessive, if it carries two copies of the same recessive allele. Heterozygous on the other hand, means that the organisms has two different alleles of a gene.
8. The correct answer is that the children will all have type AB blood. Both A and B alleles are dominant over O. as a result, individuals who have an AO genotype will have an A phenotype. The A and B alleles are codominant. When two alleles for a trait are equally expressed with neither being recessive or dominant, it creates codominance.
9. I believe the disease inheritance pattern described above by the cart shows Sex linked recessive inheritance pattern and in a cross between two heterozygous individuals there is a 50 percent chance for the second child born to be affected.
10. The answer for the question is 50 % percent.
I think that the infection design that is described above is a sex linked recessive legacy design and in a cross between two heterozygous individuals, there will be a half or 50 percent probability or possibility for the second child to be influenced.
