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2 years ago

Does anyone have any idea on how to solve this,or have some kind of formula to help me???

Mathematics

1 answer:

Stels [109]2 years ago

3 0

Yes so it would be for the first one sin0=0 then you would do sin^-1(0), sin^-1(15) same for cos it would be cos^-1(Angle your looking for here)

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4÷25times4÷100times4÷4

notsponge [240]

Answer:

0.0064 is your answer

Step-by-step explanation:

because 4÷25 = 0.16 and 4÷100=0.04 and of course 4÷4=1

When the 0.16 and 0.04 that gets 0.0064

3 0

3 years ago

Find the mean of the data in the dot plot below.

Allushta [10]

Answer:

the mean is 83.6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago

I need serious help grades go in tonighttt

attashe74 [19]

Rewrite it from least to greatest and set it up like shown

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2 years ago

Plssssss heeeelp (NOOOOO LINKS!)

ahrayia [7]

-40) No
0) No
-5) No
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21)Yes

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3 years ago