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Misha Larkins [42]
3 years ago
6

PLZ HELP DUE TODAY 30 POINTS

Mathematics
1 answer:
Helga [31]3 years ago
3 0

Answer:

I think she is correct

Step-by-step explanation:

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Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d​
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Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

Step-by-step explanation:

Evaluate:

\dfrac{b-3a}{bc^{2}-d}

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\

\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

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