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juin [17]
4 years ago
15

I need help with this right away. Please.

Mathematics
1 answer:
Nostrana [21]4 years ago
3 0
  1. ∠1 ≅ ∠2, AC bisects ∠DCB . . . . given
  2. ∠1 ≅ ∠3 . . . . vertical angles are congruent
  3. ∠2 ≅ ∠3 . . . . transitive property of congruence; both are ≅ ∠1 . . . (angle of ASA)
  4. AC ≅ AC . . . . reflexive property of congruence (side of ASA)
  5. ∠4 ≅ ∠5 . . . . definition of angle bisector (angle of ASA)
  6. ΔCDA ≅ ΔCBA . . . . ASA postulate
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ad-work [718]
Its 10 if its scaled down.

9-4 is 5 so it went down 5
15-5 is 10.
4 0
3 years ago
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Write an inequality that compares-6, 3, and 5
olga_2 [115]

Is that 6 or negative 6? I'll do both situations, as I can't tell (sorry!)

With negative 6:

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8 0
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A 6th grade student can complete 20 multiplication facts in 1 minute. If he works at the same rate, how long should it take him
Yakvenalex [24]
The key concept you must have to remember is that, the rate is kept constant, as what is specified in the problem. Our basis for the rate is the first situation.

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3 0
3 years ago
The square with a side length (x + 3) and an equilateral triangle with side lengths (3x-1) have the same perimeter what is the v
julia-pushkina [17]

Answer:

x = 3

Step-by-step explanation:

Side lenght of square = (x + 3)

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It is Given that:

Perimeter of square = Perimeter of equilateral triangle

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\therefore \: 4(x + 3) = 3(3x - 1) \\  \\  \therefore \: 4x + 12 = 9x - 3  \\ \\ \therefore \:12 + 3 = 9x - 4x \\  \\ \therefore \:15 = 5x \\  \\ \therefore \:x =  \frac{15}{5}  \\  \\  \huge \red{ \boxed{\therefore \:x = 3}}

3 0
4 years ago
Can somebody help me with this problem
Sergeu [11.5K]
72 unit cubes thats the answer

7 0
3 years ago
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