I need help with this right away. Please.
1 answer:
- ∠1 ≅ ∠2, AC bisects ∠DCB . . . . given
- ∠1 ≅ ∠3 . . . . vertical angles are congruent
- ∠2 ≅ ∠3 . . . . transitive property of congruence; both are ≅ ∠1 . . . (angle of ASA)
- AC ≅ AC . . . . reflexive property of congruence (side of ASA)
- ∠4 ≅ ∠5 . . . . definition of angle bisector (angle of ASA)
- ΔCDA ≅ ΔCBA . . . . ASA postulate
You might be interested in
Answer:
x+27
Step-by-step explanation:
2(2x+11)-(-5+3x)
Distribute
4x +22 +5-3x
Combine like terms
x+27
X = 3
y = -3
You will see this using any graphing tool at your disposal.
5x+1(6-4) = +1(5x6)-(5x)
this would be a hard question to answer but i think i can do it ((( nNOTTTT))))
Answer:
soory i need more points
Step-by-step explanation:
Answer:
Step-by-step explanation:
4*(x + 5) + 8x = 4*x + 4*5 + 8x
= 4x + 20 + 8x
= 4x + 8x + 20
= 12x + 20
