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lesya [120]
3 years ago
13

Anthony works at a clothing store and gets a 15% employee discount.If he purchase p pants and s shirts his total can be found us

ing the expression c=0.85 (35p+14.50s).What is the total cost for Anthony if he purchased 4 pairs of pants and 6 shirts.​
Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

$192.95

Step-by-step explanation:

$35 x 4 pants = $140

$14.50 x 6 shirts = $87

140 + 87 = $227

227(15%) = $34.05

227 - 34.05 = $192.95

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Find the circumference of a circle who's diameter is 4
BabaBlast [244]
C=pid
d=diameter
d=4
C=4pi

tada
if you want
aprox pi=3.14
C=12.56 units
4 0
3 years ago
How do I complete this​
DochEvi [55]

Answer:i dont know evaluate it

Step-by-step explanation:

3 0
2 years ago
For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

5 0
3 years ago
Julio bought 7 science fiction novels (s) and 7 comic books c) from the bookstore. His purchases can be represented by the expre
ANTONII [103]

Answer:

$92.60

Step-by-step explanation:

7($5.99) + 7($6.49)=$41.93

$41.93 + $45.43  = $87.36

$87.36 + ($87.36 × 6%=0.06)

$87.36 + (0.06 × $87.36=5.24)

$87.36 + $5.24= $92.60

7 0
3 years ago
Find the value of each variables in the parallelogram
xenn [34]

Answer:

A = 28

B = 87

Step-by-step explanation:

18 + 10 = 28

103 -16 = 87

4 0
3 years ago
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