Answer:
The interval of increase of g(x) is
.
Step-by-step explanation:
The interval of increase occurs when first derivative of given function brings positive values. Let be
, the first derivative of the function is:


The following condition must be met to define the interval of increase:

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

The solution to this inequation is:

Now, the solution to this expression in interval notation is: 
Alright, 4 to the 8th power is 4x4x4x4x4x4x4x4 which ends up as 65,536.
4 to the 5th power is the same thing but with 5 4's and that is 1,024.
All you need to do now is 65,536/1,024 = 64.
Solved! :D
Answer: Move terms to the left side−52+3=−9−5x2+3x=−9−52+3−(−9)=0−
Common factor−52+3+9=0−5x2+3x+9=0−(52−3−9)=0
Divide both sides by the same factor−(52−3−9)=0−(5x2−3x−9)=052−3−9=0
Solution=3±321 over 10
Step-by-step explanation: